使lambda表达式从泛型类

时间:2017-05-21 15:07:17

标签: c# c#-4.0 lambda expression-trees func

我有这些简单的界面:

public interface IQuery<TResult> { }

public interface IQueryHandler<in TQuery, out TResult> 
    where TQuery : IQuery<TResult> {
    TResult Handle(TQuery query);
}

并且有一些实施。我正在尝试创建一个表达式树来在指定的处理程序上调用Handle方法。我的意思是:

var query = new MyQuery(); // which MyQuery implements IQuery<int>
object handler = _someServiceProvider
    .Get<IQueryHandler<MyQuery, int>>();

此外,还有MyQueryHandler

public class MyQueryHandler : IQueryHandler<MyQuery, int> {
    public int Handle(MyQuery query) { return 20; }
}

现在,我正在尝试创建Func<object, MyQuery, int>来像这样调用:

var func = GetMethod<MyQuery, int>(handler);
var result = func(handler, query);

这是我的GetMethod实施:

    private Func<object, TQuery, TResult> GetMethod<TQuery, TResult>(object obj)
        where TQuery : IQuery<TResult> {

        var methodInfo = obj.GetType().GetMethod(nameof(IQueryHandler<TQuery, TResult>.Handle));

        var insExp = Expression.Parameter(typeof(object), "ins");

        var inputExp = Expression.Parameter(typeof(TQuery), "query");

        var instanceExp = Expression.Variable(obj.GetType(), "instance");

        var assExp = Expression.Assign(instanceExp, Expression.Convert(insExp, obj.GetType()));

        var castExp = Expression.Convert(inputExp, methodInfo.GetParameters()[0].ParameterType);

        var callExp = Expression.Call(instanceExp, methodInfo, castExp);

        var blockExp = Expression.Block(new Expression[] {
            insExp,
            inputExp,
            instanceExp,
            assExp,
            castExp,
            callExp
        });

        var func =
            Expression.Lambda<Func<object, TQuery, TResult>>(
                blockExp,
                insExp,
                inputExp).Compile();
        return func;
    }

但是,当我尝试编译Lambda时,我收到此错误:

  

发生了'System.InvalidOperationException'类型的异常   System.Core.dll但未在用户代码中处理

     

附加信息:类型的变量'instance'   'namespacespace.MyQueryHandler'从范围''引用,但事实并非如此   定义

我哪里错了?我错过了什么?你有什么主意吗?提前谢谢。

2 个答案:

答案 0 :(得分:1)

你在GetMethod中对你的表达方式所做的事情并不是很清楚,所以我不会使用它并从头开始写。

如果您想将处理程序和查询都传递给您的方法 - 您不需要将任何实例传递给GetMethod

private static Func<object, TQuery, TResult> GetMethod<TQuery, TResult>()
    where TQuery : IQuery<TResult> {
    // "query" paramter
    var query = Expression.Parameter(typeof(TQuery), "query");
    // "handler" parameter
    var handler = Expression.Parameter(typeof(object), "handler");
    // convert your "object" parameter to handler type (not type safe of course)
    // ((IQueryHandler<TQuery, TResult>) handler).Handle(query)
    var body = Expression.Call(Expression.Convert(handler, typeof(IQueryHandler<TQuery, TResult>)), "Handle", new Type[0], query);
    //(handler, query) => ((IQueryHandler<TQuery, TResult>) handler).Handle(query);
    return Expression.Lambda<Func<object, TQuery, TResult>>(body, handler, query).Compile();
}

object handler = new MyQueryHandler();
var func = GetMethod<MyQuery, int>();
var result = func(handler, query);

如果您 handler实例传递给GetMethod - 您不需要稍后将该同一实例再次传递给您创建的func - 你可以像这样重复使用相同的实例(假设当然适合你的场景):

private static Func<TQuery, TResult> GetMethod<TQuery, TResult>(object obj)
    where TQuery : IQuery<TResult> {
    // parameter
    var query = Expression.Parameter(typeof(TQuery), "query");
    // note Expression.Constant here - you use the same instance for every call
    var body = Expression.Call(Expression.Constant(obj), "Handle", new Type[0], query);
    return Expression.Lambda<Func<TQuery, TResult>>(body, query).Compile();
}

并使用它:

var query = new MyQuery(); // which MyQuery implements IQuery<int>
object handler = new MyQueryHandler();
var func = GetMethod<MyQuery, int>(handler);
var result = func(query);

答案 1 :(得分:1)

据我所知,你正试图写这个函数:

TResult f(object ins, TQuery query)
{
    var instance = (MyQueryHandler)ins;
    return instance.Handle(query);
}

要使用表达式树执行此操作,您必须在Expression.Block中声明变量,但只能指定上面的两个语句,而不是所有子表达式:

var blockExp = Expression.Block(new[] { instanceExp }, new Expression[] {
    assExp,
    callExp
});

但更简单的选择是编写以下函数:

TResult f(object ins, TQuery query)
{
    return ((MyQueryHandler)ins).Handle(query);
}

看起来像这样:

var callExp = Expression.Call(
    Expression.Convert(insExp, obj.GetType()), methodInfo, castExp);

var func =
    Expression.Lambda<Func<object, TQuery, TResult>>(
        callExp,
        insExp,
        inputExp).Compile();