答案 0 :(得分:1)
您可以将索引名称放在元组中,然后使用pd.MultiIndex.from_tuples()
,如:
import pandas as pd
import numpy as np
columns = [["A","B","C","D","E"],
["f8gh", "ht6k", "gf4h", "fs2e", "po9a"]
]
c_tuples = list(zip(*columns))
multi_columns = pd.MultiIndex.from_tuples(c_tuples)
index = [[11869, 14363, 29554, 34554, 52473, 62948],
[14414, 29806, 31109, 36081, 54936, 63887],
["+", "-", "+", "-", "+", "+"],
["1L1", "7P", "02-11", "38A", "4P", "11P"]]
i_tuples = list(zip(*index))
multi_index = pd.MultiIndex.from_tuples(i_tuples)
data = [10, 9,2,7,7,2,7,8,6,5,1,7,2,9,10,6,2,4,10,7,4,6,4,4,3,2,6,9,7,5]
pd.DataFrame(np.array(data).reshape((len(multi_index),len(multi_columns))),
index=multi_index,
columns=multi_columns)