Question

我开始学习JavaFX。我制作了一个创建形状的简单程序。

我想做基本事件驱动的执行方法，例如：

打印光标的坐标，如果它在形状内
每次光标进入形状时更改颜色，然后在形状不合时将其更改回原始颜色

以下是我所做的

import javafx.application.Application;
import javafx.scene.paint.Color;
import javafx.scene.shape.Circle;
import javafx.scene.Scene;
import javafx.stage.Stage;
import javafx.scene.Group;
import javafx.scene.shape.Rectangle;
import javafx.scene.shape.Polygon;


public class ColouredShapes extends Application {

    @Override
    public void start(Stage stage) {
        int radius = 40;
        int strokeWidth = 3;
        Color strokeColor = Color.BROWN;

        Circle circle1 = new Circle(250, 125, radius, Color.RED);
        circle1.setStroke(strokeColor);
        circle1.setStrokeWidth(strokeWidth);

        Rectangle square = new Rectangle(375, 85, 80, 80);
        square.setFill(Color.BLUE);
        square.setStroke(strokeColor);
        square.setStrokeWidth(strokeWidth);

        Polygon polygon = new Polygon();
        polygon.getPoints().addAll(new Double[]{
                50.0, 85.0,
               110.0, 60.0, 125.0, 175.0});

        polygon.setFill(Color.YELLOWGREEN);

        Group root = new Group();
        root.getChildren().addAll(circle1, square, polygon);
        Scene scene = new Scene(root, 500, 250, Color.LIGHTYELLOW);
        stage.setScene(scene);
        stage.show();

    }
    public static void maint(String[] args){
        launch(args);
    }
}

Answer 1

将输入，退出和移动处理程序的事件鼠标添加到形状

square.setOnMouseMoved(new EventHandler<MouseEvent>() {

  @Override
  public void handle(final MouseEvent event) {

      System.out.println(event.getScreenX());
      System.out.println(event.getScreenY());
    }
});
square.setOnMouseEntered(new EventHandler<MouseEvent>() {

  @Override
  public void handle(final MouseEvent event) {
    square.setFill(Color.GREEN);
  }
});
square.setOnMouseExited(new EventHandler<MouseEvent>() {

  @Override
  public void handle(final MouseEvent event) {
    square.setFill(null);

  }
});

在一定条件下协调光标位置和颜色变化 - JavaFX

1 个答案: