我为这个SparseGraph
类制作这个const_iterator有一些严重的问题
SparseGraph类:
对于这篇文章的意图和目的,可以将SparseGraph
视为边的列表(或向量矢量)列表(这通常称为邻接列表)。然后const_iterator
遍历列表列表中的每个边缘。
考虑:
template <typename NodeType, typename EdgeType>
class SparseGraph
{
public:
//...
using EdgeList = std::vector<EdgeType>;
using AdjacencyList = std::vector<EdgeList>;
//...
private:
//...
AdjacencyList m_adj_list;
//...
}
初步尝试const_iterator(嵌套类)
//----SparseGraph
template <typename NodeType, typename EdgeType>
class SparseGraph
{
public:
class const_iterator; //nested
//...
}
//----SparseGraph::const_iterator
template <typename NodeType, typename EdgeType>
class SparseGraph<NodeType, EdgeType>::const_iterator
{
private:
using NodeIterator = typename SparseGraph<NodeType, EdgeType>::AdjacencyList::const_iterator;
using EdgeIterator = typename SparseGraph<NodeType, EdgeType>::EdgeList::const_iterator;
//this is used to iterate through each edge list corresponding to each node
NodeIterator m_node_it;
//this is used to iterate through each edge in each edge list.
EdgeIterator m_edge_it;
public:
const_iterator(const NodeIterator& node_it, const EdgeIterator& edge_it)
: m_node_it{node_it}, m_edge_it{edge_it} {}
const_iterator& operator++(int)
{
//TODO
return *this;
}
//...
正如人们可能会注意到的那样,operator++()
给了我&#34;非静态参考&#34;错误:
错误:无效使用非静态数据成员&#39; SparseGraph :: m_adj_list&#39;
从:
//...
if(m_node_it == m_adj_list.end()) { //<--here,
//loop back around to the beginning
m_node_it = m_adj_list.begin(); //<--here,
}
m_edge_it = m_node_it.begin();//<--and here.
//...
初步尝试const_iterator(朋友类)
现在我们有以下几点:
//----SparseGraph
template <typename NodeType, typename EdgeType>
class SparseGraph
{
public:
friend class const_iterator; //friend
//as before...
}
//----SparseGraph::const_iterator-------------------------------------------------------------------------------------------------------------
template <typename NodeType, typename EdgeType>
class const_iterator
{
private:
using NodeIterator = typename SparseGraph<NodeType, EdgeType>::AdjacencyList::const_iterator;
using EdgeIterator = typename SparseGraph<NodeType, EdgeType>::EdgeList::const_iterator;
const SparseGraph<NodeType, EdgeType>& m_graph;
NodeIterator m_node_it;
EdgeIterator m_edge_it;
public:
const_iterator(const SparseGraph<NodeType, EdgeType>& graph,
const NodeIterator& node_it,
const EdgeIterator& edge_it)
: m_graph{graph} {}
//...
然后给我错误
错误:&#39; const_iterator&#39;没有命名类型
的
template <typename NodeType, typename EdgeType>
class SparseGraph
{
//...
public:
//...
const_iterator begin() const;
//...
}
和
错误:需要&#39; typename&#39;之前&#39; SparseGraph :: const_iterator&#39;因为&#39; SparseGraph&#39;是一个依赖范围
的
template <typename NodeType, typename EdgeType> typename
SparseGraph<NodeType, EdgeType>::const_iterator SparseGraph<NodeType, EdgeType>::begin() const
{
return const_iterator(*this, m_adj_list.begin(), m_adj_list.begin() >begin());
然后更改为
错误:没有&#39; typename SparseGraph :: const_iterator SparseGraph :: begin()const&#39;在类&#39; SparseGraph&#39;
中声明的成员函数
当我添加该类型名称时。如果我解决了第一个错误,我怀疑这会得到解决,但是我不知道那里有什么问题。此外,朋友班现在污染了包含它的任何翻译单位的范围。
我当前的代码
#ifndef SPARSE_GRAPH_H
#define SPARSE_GRAPH_H
#include <iostream>
#include <vector>
enum
{
invalid_node_index=-1
};
template <typename NodeType, typename EdgeType>
class SparseGraph
{
public:
class const_iterator;
using Node = NodeType;
using Edge = EdgeType;
using NodeList = std::vector<Node>;
using EdgeList = std::vector<Edge>;
using AdjacencyList = std::vector<EdgeList>;
private:
//...
//Similarly to the NodeList, each node index is analogous
//to its index in this list. Each element of this list contains
//a sub-list of edges associated with a particular node.
//For example, the list at index 3 will contain all edges associated
//with the node with an index of 3. This is so we can have an O(1) lookup time.
AdjacencyList m_adj_list;
//...
public:
SparseGraph() {}
//...
const_iterator begin() const;
const_iterator end() const;
//...
};
//----SparseGraph::const_iterator-------------------------------------------
template <typename NodeType, typename EdgeType>
class const_iterator
{
private:
using NodeIterator = typename SparseGraph<NodeType, EdgeType>::AdjacencyList::const_iterator;
using EdgeIterator = typename SparseGraph<NodeType, EdgeType>::EdgeList::const_iterator;
NodeIterator m_node_it;
EdgeIterator m_edge_it;
const NodeIterator m_begin;
const NodeIterator m_end;
public:
const_iterator(NodeIterator node_it,
EdgeIterator edge_it,
NodeIterator begin,
NodeIterator end)
: m_node_it{node_it}, m_edge_it{edge_it}, m_begin{begin}, m_end{end} {}
const_iterator& operator++(int)
{
//are we at the end of a valid edge list?
if(m_node_it != end && m_edge_it == m_node_it->end()) {
//move to the next non-empty edge list or to the end of the adjacency list
while(m_node_it != end && m_node_it->empty()) {
m_node_it++;
}
if(m_node_it != end) {
m_edge_it = m_node_it->begin();
}
}
else {
m_edge_it++;
}
return *this;
}
const_iterator& operator--(int)
{
//TODO
return *this;
}
const typename SparseGraph<NodeType, EdgeType>::Edge& operator*() const
{
return *m_edge_it;
}
const typename SparseGraph<NodeType, EdgeType>::Edge* operator->() const
{
return &(*m_edge_it);
}
bool operator==(const const_iterator& other) const
{
return m_node_it == other.m_node_it &&
m_edge_it == other.m_edge_it;
}
bool operator!=(const const_iterator& other) const
{
return !(*this == other);
}
};
//----SPARSE_GRAPH----------------------------------------------------------
//----PUBLIC FUNCTIONS------------------------------------------------------
//----begin()
template <typename NodeType, typename EdgeType>
typename SparseGraph<NodeType, EdgeType>::const_iterator SparseGraph<NodeType, EdgeType>::begin() const
{
return const_iterator(m_adj_list.begin(),
m_adj_list.begin()->begin(),
m_adj_list.begin(),
m_adj_list.back().end());
}
//----end()
template <typename NodeType, typename EdgeType>
typename SparseGraph<NodeType, EdgeType>::const_iterator SparseGraph<NodeType, EdgeType>::end() const
{
return const_iterator(m_adj_list.end(),
m_adj_list.end()->end(),
m_adj_list.begin(),
m_adj_list.back().end());
}
#endif // SPARSE_GRAPH_H
我的问题是,我应该怎么做呢?我应该使用嵌套的const_iterator类还是朋友的const_iterator类,或者,哪种方式是标准的?我应该如何实现const_iterator来避免这些问题?总的来说,我正在寻找一个双向const_iterator,它将迭代AdjacencyList(列表列表)中的每个Edge,而不允许更改所述AdjacencyList。
我查看了本网站上有关&#34; const_pointer实现&#34;的其他帖子,甚至还提到了Stroustrup&#34; C ++编程语言&#34;,但没有到目前为止,我已经深入了解了如何正确实现与此类似的const_iterator。
我对如何妥善解决这个问题感到不自在,所以对任何事情的任何帮助(可能与手头的主要问题无关)都会非常感激。
答案 0 :(得分:0)
通过将友元类转换为嵌套类(没有充分的理由不使用嵌套类)很容易编译它。但是,您的代码不会实例化任何模板。当你尝试这个时,真正的问题就开始了。
这里是您需要应用的差异:
friend class const_iterator; (ca. line 26) ===>
class const_iterator;
class const_iterator (ca. line 98) ===>
template <typename NodeType, typename EdgeType>
class SparseGraph<NodeType, EdgeType>::const_iterator
const_iterator SparseGraph<NodeType, EdgeType>::begin() const (ca. line 301) ===>
typename SparseGraph<NodeType, EdgeType>::const_iterator
SparseGraph<NodeType, EdgeType>::begin() const
const_iterator SparseGraph<NodeType, EdgeType>::end() const (ca. line 308) ===>
typename SparseGraph<NodeType, EdgeType>::const_iterator
SparseGraph<NodeType, EdgeType>::end() const
但是,您的代码并未实例化任何模板。当您尝试创建const_iterator并将其递增时,会出现真正的问题。也就是说,你的边缘列表,顶点列表和邻接列表类型及它们的迭代器,const迭代器和const_iterator都混合在一个大沙拉碗里。需要仔细分离和清理它们。
const_iterator类也没有复制/移动ctor,可能还有其他一些小问题。
答案 1 :(得分:0)
你原来的
错误:无效使用非静态数据成员&#39; SparseGraph :: m_adj_list&#39;
表示无法获得Y = 0.2125 R + 0.7154 G + 0.0721 B
范围内的SparseGraph
。你不需要调用它,只需存储SparseGraph :: m_adj_list的开始和结束你的const_iterator
m_adj_list.begin()