Question

我的json回复

[
     [
        {
          "header_id": 1,
          "name" : "Tom",
          "group" : "A"
        },
        {
          "header_id": 2,
          "name" : "Marry",
          "group" : "B"
         }
    ],

    [
         {
             "object_id" : 1,
             "SerialNo" : 123456
         },
         {
             "object_id" : 2,
             "SerialNo" : 89545
         }
     ],

     [
        {
           "workflow_id" : 1,
           "StatusName" : "start"
         },
         {
            "workflow_id" : 2,
            "StatusName" : "end"
          }

    ]
]

Header.class

public class Header{
    @SerializedName("header_id")
    private int HeaderID;
    @SerializedName("name")
    private String name;
    @SerializedName("group")
    private String group;
}

ObjectWork.class

public class ObjectWork {
    @SerializedName("object_id")
    private int ObjectID;
    @SerializedName("SerialNo")
    private int SerialNo;
}

WorkFlow.class

public class WorkFlow{
    @SerializedName("workflow_id")
    private int WorkflowID;
    @SerializedName("StatusName")
     private String statusName;
}

在json数组中，有三种类型的json对象。我将如何在retrofit2中设计pojo和自定义JsonDeserializer。现在我用gson解析这个。我不知道设计类来支持这个json并将它解串到pojo模型。

三江源

Answer 1

按照链接直接从JSON创建一个pojo：http://www.jsonschema2pojo.org/

package com.example;

import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;

public class Example {

@SerializedName("header_id")
@Expose
private Integer headerId;
@SerializedName("name")
@Expose
private String name;
@SerializedName("group")
@Expose
private String group;

public Integer getHeaderId() {
return headerId;
}

public void setHeaderId(Integer headerId) {
this.headerId = headerId;
}

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public String getGroup() {
return group;
}

public void setGroup(String group) {
this.group = group;
}

}

Answer 2

引入一个常见的包装器，让Gson识别出你的Gson禁止java.lang.Object覆盖（注意推荐的fieldNamesCaseThatIsAlwaysCamelCase）：

abstract class AbstractCommon {
}

final class Header
        extends AbstractCommon {

    @SerializedName("header_id")
    final int headerId = Integer.valueOf(0);

    @SerializedName("name")
    final String name = null;

    @SerializedName("group")
    final String group = null;

    @Override
    public String toString() {
        return headerId + ": " + name;
    }

}

final class ObjectWork
        extends AbstractCommon {

    @SerializedName("object_id")
    final int objectId = Integer.valueOf(0);

    @SerializedName("SerialNo")
    final int serialNo = Integer.valueOf(0);

    @Override
    public String toString() {
        return objectId + ": " + serialNo;
    }

}

final class WorkFlow
        extends AbstractCommon {

    @SerializedName("workflow_id")
    final int workflowId = Integer.valueOf(0);

    @SerializedName("StatusName")
    final String statusName = null;

    @Override
    public String toString() {
        return workflowId + ": " + statusName;
    }

}

现在介绍一个尝试识别实际类型的JsonDeserializer：

private static final Gson gson = new GsonBuilder()
        .registerTypeAdapter(AbstractCommon.class, (JsonDeserializer<AbstractCommon>) (jsonElement, type, context) -> {
            final JsonObject jsonObject = jsonElement.getAsJsonObject();
            if ( jsonObject.has("header_id") ) {
                return context.deserialize(jsonElement, Header.class);
            }
            if ( jsonObject.has("object_id") ) {
                return context.deserialize(jsonElement, ObjectWork.class);
            }
            if ( jsonObject.has("workflow_id") ) {
                return context.deserialize(jsonElement, WorkFlow.class);
            }
            throw new IllegalArgumentException("Cannot recognize: " + jsonElement);
        })
        .create();

现在你可以轻松地做到：

private static final Type commonsType = new TypeToken<List<List<AbstractCommon>>>() {
}.getType();

public static void main(final String... args)
        throws IOException {
    try ( final JsonReader jsonReader = getPackageResourceJsonReader(Q44034331.class, "arrays.json") ) {
        final List<List<AbstractCommon>> commons = gson.fromJson(jsonReader, commonsType);
        commons.stream()
                .flatMap(Collection::stream)
                .forEach(abstractCommon -> System.out.println(abstractCommon.getClass().getSimpleName() + ": " + abstractCommon));
    }
}

输出：

标题：1：汤姆   标题：2：嫁给   ObjectWork：1：123456
  ObjectWork：2：89545
  WorkFlow：1：开始
  WorkFlow：2：结束

坦率地说，我觉得你的JSON有点奇怪（假设子阵列元素真的看起来彼此相关但是解构了）：它有点像一个由内到外的结构。如果你可以控制JSON格式，我真的很赞赏你重新设计它。如果它不在您的控制之下，看起来您需要这样的东西（Gson类型适配器也可以）：

final class Wrapper {

    final Header header;
    final ObjectWork objectWork;
    final WorkFlow workFlow;

    Wrapper(final Header header, final ObjectWork objectWork, final WorkFlow workFlow) {
        this.header = header;
        this.objectWork = objectWork;
        this.workFlow = workFlow;
    }

}

private static Collection<Wrapper> combine(final List<List<AbstractCommon>> commons) {
    @SuppressWarnings({ "unchecked", "rawtypes" })
    final List<Header> headers = (List) commons.get(0);
    @SuppressWarnings({ "unchecked", "rawtypes" })
    final List<ObjectWork> objectWorks = (List) commons.get(1);
    @SuppressWarnings({ "unchecked", "rawtypes" })
    final List<WorkFlow> workFlows = (List) commons.get(2);
    final Iterator<Header> headerIterator = headers.iterator();
    final Iterator<ObjectWork> objectWorkIterator = objectWorks.iterator();
    final Iterator<WorkFlow> workFlowIterator = workFlows.iterator();
    final Collection<Wrapper> wrappers = new ArrayList<>();
    while ( headerIterator.hasNext() && objectWorkIterator.hasNext() && workFlowIterator.hasNext() ) {
        final Header header = headerIterator.next();
        final ObjectWork objectWork = objectWorkIterator.next();
        final WorkFlow workFlow = workFlowIterator.next();
        final Wrapper wrapper = new Wrapper(header, objectWork, workFlow);
        wrappers.add(wrapper);
    }
    return wrappers;
}

combine(commons)
        .forEach(wrapper -> System.out.println(wrapper.header + ", " + wrapper.objectWork + ", " + wrapper.workFlow));

输出：

1：汤姆，1：123456，1：开始
2：结婚，2：89545,2：结束

retrofit2中嵌套json数组（多个类型对象）的JsonDeserializer

2 个答案: