Question

作为情侣日R＆amp; D，我发现一些解决方案可以做到这一点，但是我无法通过改装2.3版本显示JSON API的任何响应。我知道这个问题可能会重复，但是，任何人都可以帮助我。这就是JSON API的样子

{
 "GetInsertPageInfoResponse": {
  "Request": {
   "IsValid": "True",
   "GetInsertPageInfoRequest": null
   },
  "GetInsertPageInfo": {
   "1": [
    {
     "cat_name": "test1",
     "image_thumb_path": "insertPage/thumb/taputapu",
     "image_original_path": "upload/insertPage/original/book",
     "cat_icon_path": "upload/insertPage/cat_icon/icon.png",
     "cat_version": "8",
     "item_id": "1",
     "item_name": "01.jpg"
    }
   ],
   2: [
    {
     "cat_name": "test2",
     "image_thumb_path": "upload/insertPage/thumb/taputapu",
     "image_original_path": "photobook/upload/insertPage/original/book",
     "cat_icon_path": "upload/insertPage/cat_icon/icon.png",
     "cat_version": "6",
     "item_id": "3",
     "item_name": "08.jpg"
    }
   ]
 }
}}

这是我试图解析json，但它仍然无法正常工作

public class APIClient {
    private static Retrofit retrofit = null;
    public static Retrofit getClient(String baseUrl) {
        if (retrofit==null) {
            retrofit = new Retrofit.Builder()
                    .baseUrl(baseUrl)
                    .addConverterFactory(GsonConverterFactory.create())
                    .build();
        }
        return retrofit;
    }

}

这就是我获得服务的方式

    public interface APIService {
    @GET("?Service=Core&Operation=GetInsertPageInfo")
    Call<GetInsertPageInfoResponse> getInsertPageInfoCall();
   }

public class APIUtils {
    public static APIService getSOService() {
        return APIClient.getClient(API_ROOT_URL).create(APIService.class);
    }
}

我尝试使用此POJO

public class GetInsertPageInfoResponse {
    @SerializedName("GetInsertPageInfoResponse")
    @Expose
    private GetInsertPageInfo getInsertPageInfo;
}

public class GetInsertPageInfo {
    @SerializedName("GetInsertPageInfo")
    @Expose
    private Map<String, List<AsobieItem>> mPageInfo;

    public Map<String, List<AsobieItem>> getmPageInfo() {
        return mPageInfo;
    }

    public void setmPageInfo(Map<String, List<AsobieItem>> mPageInfo) {
        this.mPageInfo = mPageInfo;
    }
}

public class AsobieItem {
    @SerializedName("cat_name")
    @Expose
    private String cateName;
    @SerializedName("image_thumb_path")
    @Expose
    private String imageThumbPath;
    @SerializedName("image_original_path")
    @Expose
    private String imageOriginalPath;
    @SerializedName("cat_icon_path")
    @Expose
    private String catIconPath;
    @SerializedName("cat_version")
    @Expose
    private String catVersion;
    @SerializedName("item_id")
    @Expose
    private String itemId;
    @SerializedName("item_name")
    @Expose
    private String itemName;
}

UPDATE !! 这就是我在Activity类中使用retrofit 2的请求：

APIService mApiService = APIUtils.getSOService();

public void callAPIGetInsertPageInfo() {
        mApiService.getInsertPageInfoCall().enqueue(new Callback<GetInsertPageInfoResponse>() {
            @Override
            public void onResponse(Call<GetInsertPageInfoResponse> call, Response<GetInsertPageInfoResponse> response) {
                if (response.isSuccessful()) {
                    Log.i("Response", response.body().toString());
                    Log.d("GetResponse",  response.raw().toString());


                } else {
                    int statusCode = response.code();
                    // handle request errors depending on status code
                }
            }

            @Override
            public void onFailure(Call<GetInsertPageInfoResponse> call, Throwable t) {
                //TODO 
            }
        });
    }

当我记录响应时，我看到此错误：Response ID 525295 is not served in this process.

Answer 1

几天后，我发现了自己。我使用HashMap<>和List<List<Item>>来匹配那种JSON API。我声明了一个POJO，其中包含List<Item>和id来识别它们

public class ListWithId {
    private List<Item> items;
    private int id;

    public ListWithId(List<Item> items, int id){
        this.items = items;
        this.id = id;
    }

    public List<Item> getItems() {
        return items;
    }

    public void setItems(List<Item> items) {
        this.items = items;
    }

    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }
}

在Activity.class我使用此Object将所有数据打入

 private List<ListWithId> listTC;


public void callAPIGetInsertPageInfo() {
        mApiService.getInsertPageInfoCall(Constants.CORE_PARAM, Constants.GET_RESPONSE_PARAM).enqueue(new Callback<GetInsertPageInfoResponse>() {
            @Override
            public void onResponse(Call<GetInsertPageInfoResponse> call, Response<GetInsertPageInfoResponse> response) {
                if (response.isSuccessful()) {
                    for (Map.Entry<Integer, List<AsobieItem>> entry : response.body().getGetInsertPageInfo().getmPageInfo().entrySet()) {
                        listTC.add(new ListWithId(entry.getValue(), entry.getKey()));
                    }

                    mAdapter = new MyAdapter(Activity.this, listTC);
                    refreshAdapter();
                    // set adapter for list view

                    mListView.setAdapter(mAdapter);
                } else {
                    int statusCode = response.code();
                    // handle request errors depending on status code
                }
            }

            @Override
            public void onFailure(Call<GetInsertPageInfoResponse> call, Throwable t) {
                //TODO FAIL
            }
        });
    }

当我获得Logged获取密钥和值时。它会像这样

Keys: 1
Values: "1":[{ListItem}, {ListItem}]
Keys: 2
Values: "2":[{ListItem2}, {ListItem2}]

Answer 2

您可以使用

HashMap<Integer,List<MyObject> GetInsertPageInfo

Answer 3

首先，我认为你应该改变你的基本网址。例如：如果您base_url现在是abc.com/help/dosth - ＆gt;您应该将base_url更改为abc.com/

他们将API interface重新实现为

public interface APIService {
    @GET("help/dosth")
    Call<GetInsertPageInfoResponse> getInsertPageInfoCall(@Query("Service") String service, @Query("Operation") String operation);
}

然后用params调用API，看看会发生什么。在你的代码中我看到POJO对象仍然不完全正确，但让我们稍后再看

如何改进2.3可以使用键和值解析嵌套的jsonObject和多个Array

3 个答案: