Question

我的代码正在构建一个网页，我根据计算机ID（machine_id）显示多个数据表。最终用户希望能够滚动单个页面上的所有表格，而不是每台机器都有一个页面。

附件是页面的截图（实际上在页面上显示的不仅仅是两个表）。我可以修改我的代码，以便我在machine_id更改时不会在While循环中进行多次查询吗？

$db = new Database();

$result = mysqli_query($conn, "SELECT machine_id, machine_name, display_order FROM machines WHERE active_board = 'YES' ORDER BY display_order ASC");

echo "<table>";

while ($row = mysqli_fetch_assoc($result))  {

    $mach_id = $row["machine_id"];
    $machine_name = $row["machine_name"];
    $presspage = $row["machine_id"];
    $machine_name = $row["machine_name"];
    $daycount = '7';

    $rows = $db -> select("SELECT a.machine_id, a.job_id, a.component, a.production_date, a.colors, a.hours, a.quantity, a.is_completed, a.artwork_image,
          j.job_id, j.job_number, j.customer_id, j.job_name, j.total_cost, j.due_date, j.rework, j.pps, j.personalization, j.shipped, j.wave_csr,
          c.customer_id, c.customer_name, c.board_color, c.text_color, u.full_name, p.component_name, d.delivery_method
          FROM job_assignments a
          LEFT JOIN jobs j ON a.job_id = j.job_id
          LEFT JOIN customers c ON j.customer_id = c.customer_id
          LEFT JOIN users u ON j.wave_csr = u.user_id
          LEFT JOIN job_components p ON a.component = p.component_code
          LEFT JOIN delivery_methods d ON j.method_id = d.method_id
          WHERE a.machine_id = $presspage
          ORDER BY j.job_number ASC");

echo "<tr>";
echo "<td>";

echo "<div id='dhtmlgoodies_dragDropContainer'>";

 echo   "<div id='dhtmlgoodies_mainContainer' align='center' vertical-align='middle'>";

    echo "<h2>" . $machine_name . "</h2>";

    for($x=0;$x<$daycount;$x++) {
            $thehours = 0;
            $theday = date('l M d', strtotime($date . " + {$x} day"));
            $theday2 = date('Y-m-d', strtotime($date . " + {$x} day"));
            $daycode = date('Md', strtotime($date . " + {$x} day"));
            $totalhours = 0;
            $pastdue_hours = 0;
            $totalvalue = 0.00;

            echo "<div style='width:180px; height:1500px; '>";
            echo "<p>" . $theday . "</p>";

            foreach ($rows as $row) {
                $prod_date = $row["production_date"];
                $shipped = $row["shipped"];
                $hours = $row["hours"];
                $value = $row["total_cost"];
                $assignment_completed = 0;
                $is_completed = $row["is_completed"];

                if (($prod_date < date('Y-m-d')) AND ($shipped == 'NO') ) {
                    $prod_date = date('Y-m-d');
                };
                        ...

Screenshot example of web page.

Answer 1

您可以将这两个查询加入

SELECT m.machine_id, m.machine_name, m.display_order, a.job_id, a.component, a.production_date, a.colors, a.hours, a.quantity, a.is_completed, a.artwork_image,
  j.job_id, j.job_number, j.customer_id, j.job_name, j.total_cost, j.due_date, j.rework, j.pps, j.personalization, j.shipped, j.wave_csr,
  c.customer_id, c.customer_name, c.board_color, c.text_color, u.full_name, p.component_name, d.delivery_method
FROM 
  machines m
  LEFT JOIN job_assignments a USING (machine_id)
  LEFT JOIN jobs j ON a.job_id = j.job_id
  LEFT JOIN customers c ON j.customer_id = c.customer_id
  LEFT JOIN users u ON j.wave_csr = u.user_id
  LEFT JOIN job_components p ON a.component = p.component_code
  LEFT JOIN delivery_methods d ON j.method_id = d.method_id
WHERE a.machine_id = $presspage and m.active_board = 'YES'
ORDER BY m.display_order, j.job_number;

Answer 2

您可以先将所有机器ID从第一个查询中获取到一个数组中，然后一次性对该数组中的所有机器ID执行第二个查询。以下是一个示例：

$db = new Database();


$result = mysqli_query($conn, "SELECT machine_id, machine_name, display_order FROM machines WHERE active_board = 'YES' ORDER BY display_order ASC");

$active_board_machine_ids = array();
while ($row = mysqli_fetch_assoc($result))  {
  $active_board_machine_ids[] = $row["machine_id"];
}

$rows = $db -> select("SELECT a.machine_id, a.job_id, a.component, a.production_date, a.colors, a.hours, a.quantity, a.is_completed, a.artwork_image,
      j.job_id, j.job_number, j.customer_id, j.job_name, j.total_cost, j.due_date, j.rework, j.pps, j.personalization, j.shipped, j.wave_csr,
      c.customer_id, c.customer_name, c.board_color, c.text_color, u.full_name, p.component_name, d.delivery_method
      FROM job_assignments a
      LEFT JOIN jobs j ON a.job_id = j.job_id
      LEFT JOIN customers c ON j.customer_id = c.customer_id
      LEFT JOIN users u ON j.wave_csr = u.user_id
      LEFT JOIN job_components p ON a.component = p.component_code
      LEFT JOIN delivery_methods d ON j.method_id = d.method_id
      WHERE a.machine_id IN ('".implode("','",$active_board_machine_ids)."')
      ORDER BY j.job_number ASC");

我可以在While循环中避免此查询以加快页面加载吗？

2 个答案: