我正在尝试使用我的python代码从不同的端点提取数据,并使用matplotlib提供相同的数据来绘制图形。我在读取数据时没有任何问题但是当我通过提供数据来调用绘制图形的方法时,我会看到由matplot lib引起的间歇性错误。以下是错误细节。
Traceback (most recent call last):
File "C:\Python35\lib\site-packages\slackbot\dispatcher.py", line 55, in _dispatch_msg_handler
func(Message(self._client, msg), *args)
File "C:\PycharmProjects\SlackBot\src\plugins\bot_response.py", line 248, in checkmarx
draw_chart.riskscore_bar(top_riskscore, project_name, "output_files", "riskscore_bar.png")
File "C:\PycharmProjects\SlackBot\src\drawchart.py", line 111, in riskscore_bar
fig, ax = plt.subplots()
File "C:\Python35\lib\site-packages\matplotlib\pyplot.py", line 1202, in subplots
fig = figure(**fig_kw)
File "C:\Python35\lib\site-packages\matplotlib\pyplot.py", line 535, in figure
**kwargs)
File "C:\Python35\lib\site-packages\matplotlib\backends\backend_tkagg.py", line 81, in new_figure_manager
return new_figure_manager_given_figure(num, figure)
File "C:\Python35\lib\site-packages\matplotlib\backends\backend_tkagg.py", line 98, in new_figure_manager_given_figure
icon_img = Tk.PhotoImage(file=icon_fname)
File "C:\Python35\lib\tkinter\__init__.py", line 3403, in __init__
Image.__init__(self, 'photo', name, cnf, master, **kw)
File "C:\Python35\lib\tkinter\__init__.py", line 3359, in __init__
self.tk.call(('image', 'create', imgtype, name,) + options)
RuntimeError: main thread is not in main loop
我已尝试从stackoverflow查看其他相同的错误消息,但它没有帮我解决这个问题。下面是我调用错误的代码片段。
def riskscore_bar(self, top_riskscore, project_id, output_folder,
output_filename):
logger.debug("Inside method plotgraph in drawchart.py.")
y_pos = np.arange(len(project_id))
width = .4
fig, ax = plt.subplots()
graph = ax.bar(y_pos+1, top_riskscore, width, color='#feb308')
ax.set_ylabel('Risk Score')
ax.set_title('Summary')
ax.set_xticks(y_pos + 1)
ax.set_xticklabels(project_id,fontsize=5, rotation=45 )
def autolabel(rects):
for rect in rects:
height = rect.get_height()
ax.text(rect.get_x() + rect.get_width()/2., 1.001*height,
'%d' % int(height),
ha='center', va='bottom')
autolabel(graph)
pylab.savefig(os.path.join(os.path.abspath(os.path.dirname(__file__)), '..', output_folder,output_filename))
错误似乎发生在" fig,ax = plt.subplots()"。关于如何解决这个问题的任何想法?
答案 0 :(得分:0)
这可以通过在将 matplotlib.pyplot 作为 plt 导入后立即添加 plt.switch_backend('agg') 来解决。如下图
import matplotlib.pyplot as plt
plt.switch_backend('agg')