Question

我很难将天与数组进行比较

这是我的阵列：

array:2 [
0 => {
  "id": 1
  "time_in": "08:00:00"
  "time_out": "17:00:00"
  "days": "["tuesday","thursday","saturday"]"
}
1 => {
  "id": 2
  "time_in": "09:00:00"
  "time_out": "18:00:00"
  "days": "["monday","wednesday","friday"]"
}
  ]

注意：天数是来自数据库的json数据

我有这个变量日

$day = 'friday';

我只想用＆＃39;星期五＆＃39;来获取数组数据。在他们的日子里请帮助我解决我的代码我不知道应该如何操纵它或者我将使用什么代码来获取它

我希望有这个输出：

$day = 'friday';

1 => {
      "id": 2
      "time_in": "09:00:00"
      "time_out": "18:00:00"
      "days": "["monday","wednesday","friday"]"
    }

因为它当天有星期五

Answer 1

您可以使用 in_array（）函数，该函数在数组中搜索特定值。

搜索 $ day =＆＃34;周五＆＃34; ，我将另一个数组声明为 $ b 并将过滤值添加到其中。

试试这个：

$array = array(array("id"=>"1","time_in"=>"08:00:00","time_out"=>"17:00:00","days"=>'["tuesday","thursday","saturday"]'),
array("id"=>"2","time_in"=>"09:00:00","time_out"=>"18:00:00","days"=>'["monday","wednesday","friday"]'));
      $day = "friday";
      $b = array();
      foreach ($array as $val) {
           if (in_array($day,$val['days'])) {
               $b[] = $val;
           }
       }

    print_r($b);

Answer 2

使用in_array查找数组

中的数据

foreach($your_array as $obj){
   if(in_array($day, $obj->days)){
      return $obj;
   }
}

Answer 3

让我们说您的JSON数据定义为$json：

$json_array = json_decode($json);

$result = [];

foreach($json_array as $arr){
    if(in_array($day,$arr->days)){
        $result[] = $arr;
    }
}

Answer 4

<?php

// the day you want
$day = 'friday';

// decode json to php array
$days = json_decode($yourJSONArrayFromDatabase, true);

for ($i=0; $i < count($days); $i++)
{
    if (in_array($day, $days[$i]['days'])) {
        echo json_encode($days[$i]);
        break;
    }
}

我应该如何将我的数据与数组json进行比较

4 个答案: