Question

我正在尝试通过JSON解析来获取数据，但无法将数据提取到我的应用程序中。请帮助

这是我的获取数据链接

HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost("http://192.168.0.17//my_home/services/getcategorydata.php?city=Islamabad"); //YOUR PHP SCRIPT ADDRESS 
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();
            isr = entity.getContent();

虽然这是另一个

  BufferedReader reader = new BufferedReader(new InputStreamReader(isr,"iso-8859-1"),8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                    sb.append(line + "\n");
            }
            isr.close();

            result=sb.toString();

最后

  JSONArray jArray = new JSONArray(result);



       for(int i=0; i<jArray.length();i++){
           //dic json call
           //then get data 
           //
           JSONObject json = jArray.getJSONObject(i);


how fetch array of php     


       switch (i)
       {
       case 0:
       {
         Care_title.setText(json.getString("name"));
         Care_minutz.setText(json.getString("rate") );
         child_mintz_.setText(json.getString("hour"));
         break;
       }
       So on....

而我的php获取数据是

{"type":"1","data":[{"name":"Delivery","title":"Delivery","rate":"500 RS","icon":"http:\/\/localhost\/services\/images\/category_icon\n\/delivery.png","publishtype":"PUBLISHED","timestamp":"2015-08-25 12:32:50"},{"name":"Care","title":"Care","rate":"400 RS","icon":"http:\/\/localhost\/services\/images\/category_icon\n\/care.png","publishtype":"PUBLISHED","timestamp":"2015-08-25 12:32:43"}],"title":"Message","message":"","_explicitType":null}

Answer 1

JSONObject json=new JSONObject(response);
JSONArray dataArray=json.getJSONArray("data");
for(int i=0;i<dataArray.length();i++)
{
    JSONObject data=dataArray.getJSONObject(i);
    String name=data.getString("name");
}

Answer 2

您可以使用Volley Library来解析数据。

private void JsonCall() throws JSONException {
    // TODO Auto-generated method stub

    String url = "http://192.168.0.17//my_home/services/getcategorydata.php?city=Islamabad";


    JsonObjectRequest jsonobject = new JsonObjectRequest(Method.PUT, url, null, new Response.Listener<JSONObject>() {

        @Override
        public void onResponse(JSONObject arg0) {

            //Your Json Responce
        }
    }, new Response.ErrorListener() {

        @Override
        public void onErrorResponse(VolleyError arg0) {
            // TODO Auto-generated method stub
            Log.e("Error Code:", arg0 + "");

        }
    })
    };
    AppController.getInstance().addToRequestQueue(jsonobject, "UPDATETIMELINE");

}

创建一个应用程序调用AppController.java。

如何获取数据数组，以便从我的服务器获取数据

2 个答案: