Question

我目前正在SQL Server中开发一个报告。假设我有3列。

FirstName | LastName | URL's
----------+----------+------------------------------------------------
Tiffany   | Smith    | www.example.com/accountname=%3Dtiffany%7Lsmith

网址格式始终为：

www.example.com/accountname=%3Dname%7Lname

如何使用FirstName和LastName中的值填充网址列，如上例所示？

Answer 1

你可以做这样的事情

declare @firstname varchar(10) = 'hello'

declare @lastname varchar(10) = 'there'

select 'www.example.com/accountname=%3D'+@firstname+'%7L'+@lastname as url

返回的网址是

www.example.com/accountname=%3Dhello%7Lthere

只需使用列名替换变量

Answer 2

使用连接：

create table #temp
(
firstname varchar(50),
lastname  varchar(50)
)

insert into #temp (firstname, lastname) values
('tiffany', 'smith'),
('john', 'doe')

select 
firstname
, lastname
, concat('www.example.com/accountname=%3D', firstname, '%7L', lastname) as 'url'
from #temp

Answer 3

;With cte(FirstName , LastName , [URL's])
AS
(
SELECT 'Tiffany', 'Smith', 'www.example.com/accountname=%3D%7L'  Union all 
SELECT 'john', 'doe',Null
)
SELECT FirstName
    ,LastName
    ,ISNULL(STUFF(STUFF([URL's], CHARINDEX('%3D', [URL's]) + 3, 0, FirstName), 
            CHARINDEX('%7L', STUFF([URL's], CHARINDEX('%3D', [URL's]) + 3, 0, FirstName)),
                LEN(LastName), '%7L' + LastName), 'NA') AS [URL's]
FROM cte

输出

FirstName   LastName    [URL's]
---------------------------------------------------------------------
Tiffany     Smith       www.example.com/accountname=%3DTiffany%7LSmith
john        doe         NA

如何使用其他2列的值填充已包含URL的列？

3 个答案: