SQL Server将一列视为两列

Question

表格如下：

对于与public int getPos(int position) { return position; } 相同的RDATE和TAGNAME应该：

对于任何帮助非常感谢。

'WOJ11_%'

CREATE TABLE [dbo].[RD]( [RDATE] [datetime] NULL, [TAGNAME] [nvarchar](50) NULL, [RVALUE] [float] NULL, [RMINVALUE] [float] NULL, [RMAXVALUE] [float] NULL ) ON [PRIMARY] INSERT INTO [dbo].[RD] VALUES ('2017-04-04 18:00:00.000', 'WOJ11_Q1', 0, 0, 0), ('2017-04-04 18:00:00.000', 'WOJ11_P2', 0, 0, 0), ('2017-04-04 18:00:00.000', 'WOJ11_P1', 0, 0, 0), ('2017-04-04 19:00:00.000', 'WOJ11_Q1', 65.12, 61.52, 68.52), ('2017-04-04 19:00:00.000', 'WOJ11_P2', 5.82833333333333, 5.796, 5.874), ('2017-04-04 19:00:00.000', 'WOJ11_P1', 6.18733333333333, 6.158, 6.227), ('2017-04-04 20:00:00.000', 'WOJ11_Q1', 75.72, 72.68, 77.44), ('2017-04-04 20:00:00.000', 'WOJ11_P2', 5.7345, 5.698, 5.776), ('2017-04-04 20:00:00.000', 'WOJ11_P1', 6.07925, 6.04, 6.128), ('2017-04-04 21:00:00.000', 'WOJ11_Q1', 72.2, 68.32, 79.56), ('2017-04-04 21:00:00.000', 'WOJ11_P2', 5.80575, 5.688, 5.884), ('2017-04-04 21:00:00.000', 'WOJ11_P1', 6.109, 6.021, 6.168), ('2017-04-04 22:00:00.000', 'WOJ11_Q1', 66.48, 59.68, 70.72), ('2017-04-04 22:00:00.000', 'WOJ11_P2', 5.86675, 5.766, 5.972), ('2017-04-04 22:00:00.000', 'WOJ11_P1', 6.175, 6.119, 6.236); 的输出表（3个标签）应如下所示：

'WOJ11_%'

值：

CREATE TABLE [dbo].[RD_OUTPUT](
    [RDATE] [datetime] NULL,
    [TAGNAME_P1_RVALUE] [float] NULL,
    [TAGNAME_P1_RMINVALUE] [float] NULL,
    [TAGNAME_P1_RMAXVALUE] [float] NULL,
    [TAGNAME_P2_RVALUE] [float] NULL,
    [TAGNAME_P2_RMINVALUE] [float] NULL,
    [TAGNAME_P2_RMAXVALUE] [float] NULL,
    [TAGNAME_Q1_RVALUE] [float] NULL,
    [TAGNAME_Q1_RMINVALUE] [float] NULL,
    [TAGNAME_Q1_RMAXVALUE] [float] NULL
) ON [PRIMARY]

Answer 1

您可以使用简单的支点

select * from (
select * from #yourtable where Tagname like 'WOJ11_%' ) a
pivot (max(RValue) for TagName in ([WOJ11_P1],[WOJ11_P2],[WOJ11_Q1])) p

如果您需要多个标记名来进行动态查询以生成列并在“IN”子句中提供