if object_id( 'tempdb.dbo.#ctp', 'u' ) is not null
drop table #ctp ;
create table #ctp( id int, mastername varchar( 16 ) ) ;
insert into #ctp values( 1, 'Big Boy' ) ;
if object_id( 'tempdb.dbo.#client', 'u' ) is not null
drop table #client ;
create table #client( id int, name varchar(16 ), type int ) ;
insert into #client values( 1, 'ABC', 5 ) ;
insert into #client values( 2, 'XYZ', 6 ) ;
if object_id( 'tempdb.dbo.#ctpclient', 'u' ) is not null
drop table #ctpclient ;
create table #ctpclient( id int, ctpfk int, clientfk int ) ;
insert into #ctpclient values( 1, 1, 1 ) ;
insert into #ctpclient values( 2, 1, 2 ) ;
select tp.mastername
, c.name
, c.type
, cc.ctpfk
, cc.clientfk
from #ctp tp
join #ctpclient cc
on tp.id = cc.ctpfk
join #client c
on c.id = cc.clientfk
;
当前输出
mastername|name|type
Big Boy|ABC|5
Big Boy|XYZ|6
而不是两行输出,我希望输出如下:
mastername|nameone|nametwo
Big Boy | ABC | XYZ
这样做的最佳方法是什么,因为我有很多表,比如#ctpclient?
答案 0 :(得分:0)
假设您总是有2行,则可以使用交叉表(也称为条件聚合)。它看起来像这样。
with SortedValues as
(
select tp.mastername
, c.name
, ROW_NUMBER() over (partition by mastername order by clientfk) as RowNum
from #ctp tp
join #ctpclient cc on tp.id = cc.ctpfk
join #client c on c.id = cc.clientfk
)
select mastername
, MAX(case when RowNum = 1 then name end) as NameOne
, MAX(case when RowNum = 2 then name end) as NameTwo
from SortedValues
group by mastername
如果你有不同的数字,你仍然可以完成,但它有点复杂。