Question

有人可以帮我想一个智能算法吗？

问题

JSON数据看起来有点像这样（无法提供真实数据：/）：

{
    "$id": "1",
    "Start": 1000,
    "End": 1200,
    "Account": {
        "$id": "2",
        "id": "af51f511-e851-4d01-808b-2fa3c070d3ad",
        "aLotMoreInfo": "cool",
        "Parents": {
            "$id": "3",
            "id": "73d7a1f1-82e8-4a7e-bccb-838a251e1a38",
            "aLotMoreInfo": "notcool",
            "Parents": null,
            "Children": {
                "ref": 2
            }
        },
        "Children": null
    }
}

无论如何，现在的问题是它包含ref，后面有一个值。上面的JSON应该是这样的：

{
    "$id": "1",
    "Start": 1000,
    "End": 1200,
    "Account": {
        "$id": "2",
        "id": "af51f511-e851-4d01-808b-2fa3c070d3ad",
        "aLotMoreInfo": "cool",
        "Parents": {
            "$id": "3",
            "id": "73d7a1f1-82e8-4a7e-bccb-838a251e1a38",
            "aLotMoreInfo": "notcool",
            "Parents": null,
            "Children": {
                "$id": "2",
                "id": "af51f511-e851-4d01-808b-2fa3c070d3ad",
                "aLotMoreInfo": "cool",
                "Parents": {
                    "$id": "3",
                    "id": "73d7a1f1-82e8-4a7e-bccb-838a251e1a38",
                    "aLotMoreInfo": "notcool",
                    "Parents": null,
                    "Children": null
                },
                "Children": null
            },
            "Children": null
        }
    }
}

我需要知道两件事：

如何轻松获取之前陈述的JSON数据
如何复制它，但每个值都设置值Children为null 时间？

我希望有人知道如何做到这一点，因为我无法想到一个聪明的方法......

JSON递归数据~PHP CODE

0 个答案: