Question

我有“IT / Internet / Web Development / Ajax”形式的字符串。我解析它并创建一个像

的JSON对象

[{
  "name": "IT",
  "subcategories":[
   {
    "name": "Internet",
    "subcategories" : [
    {
      "name": "Web Development",
       "subcategories" : [
       {
        "name":"Ajax"
        }]}]}]

我通过

创建JSON对象

$input = "IT/Internet/Web Development";
$items = explode("/", $input);

$parent = null;
$firstObject = null;
while (count($items))
{
 $object = new StdClass();
 $item = array_shift($items);
 $object->name = $item;
 if (count($items) == 0) {
    $object->subcategories=NULL; // I made this null in order to know that this is the last item of the string that comes in
 }
 if ($parent)
    $parent->subcategories = array($object);
 else
    $firstObject = $object;

  $parent = $object;
}
array_push($category_collection, $firstObject); //$category_collection is an array
}

当另一个字符串出现时，例如“IT / Internet / Browsers”，我希望能够解析创建的类别并将“浏览器”放在正确的位置作为Internet的子类别，那么我的JSON对象看起来像

 [{
  "name": "IT",
  "subcategories":[
   {
    "name": "Internet",
    "subcategories" : [
    {
      "name": "Web Development",
       "subcategories" : [
       {
          "name":"Ajax"
        }],
        {
         "name":"Browsers" 
         }}]}]

我在编写一个递归函数时遇到问题，该函数只是循环JSON对象以在正确的位置对所有内容进行分类。我现在正在做的是

    $arrlength = count($category_collection); //count the size of the array
    $input = "IT/Internet/Browsers";
    $items = explode("/",$input);
    $tempVariable = array_shift($items);
    $flag = false;
    for ($x = 0; $x < $arrlength; $x++) {
      //Here I check if the first a category with that name already exists
        if ($category_collection[$x]['name'] == $tempVariable) {
            $flag = true;

                    //Now here is where im having problems doing the recursion to check  if the subcategory2 already exists and then if subcategory 3 and so on...

        }

    }

如果有人能指引我正确的方向，那将非常感激

Answer 1

请尝试这个（未经测试，可能有一些错误需要纠正，我在这里提供帮助）：

function boolean check_is_good($array, $input)
{
$element = array_shift($input);
for ($x = 0; $x < count($array), $x++) {
        if ($array[$x]['name'] == $element){
           if ((!isset($array[$x]['subcategories']) && (count($input) == 0))
              return (true);
           else if ((!isset($array[$x]['subcategories']) && (count($input) != 0))
              return (false);
           $newArray = $array[$x]['subcategories'];
           return (check_is_good($newArray, $input));
        }
    }
  return (false);
}

函数return true全部在正确的位置

你必须在parameter1中传递一个代表你的JSON的数组（在你的例子中为$ category_collecton）

你必须在参数2中传入一个包含所有元素的数组（在你的例子中为$ items）

Answer 2

这是一个完整的函数，它应该可以工作，如果需要，可以将它转换为json：

$categoriesCollection = array();

$input = "IT/Internet/Web Development";
updateCategoriesCollection(explode('/', $input), $categoriesCollection);
$input = "IT/Internet/Browsers";
updateCategoriesCollection(explode('/', $input), $categoriesCollection);

function updateCategoriesCollection(array $categoriesList, array &$categoriesCollection)
{
    $name = array_shift($categoriesList);
    $category = null;
    foreach ($categoriesCollection as $key => $value)
    {
        if ($value->name == $name)
        {
            $category = $value;
            break;
        }
    }
    if (!$category)
    {
        $category = new StdClass;
        $category->name = $name;
        $categoriesCollection[] = $category;
    }

    if (!empty($categoriesList))
    {
        if (empty($category->subcategories)) $category->subcategories = array();
        updateCategoriesCollection($categoriesList, $category->subcategories);
    }
}
var_dump($categoriesCollection);

输出：

Array
(
    [0] => stdClass Object
        (
            [name] => IT
            [subcategories] => Array
                (
                    [0] => stdClass Object
                        (
                            [name] => Internet
                            [subcategories] => Array
                                (
                                    [0] => stdClass Object
                                        (
                                            [name] => Web Development
                                        )

                                    [1] => stdClass Object
                                        (
                                            [name] => Browsers
                                        )

                                )

                        )

                )

        )

)

递归搜索功能

2 个答案: