Question

我想和scala.ref.WeakReference一起玩。但是，在尝试实现大事之前，我想尝试检查scala控制台中的行为。我尝试了一些但我无法获得被取消引用的对象。这是我的尝试之一：

> class A
defined class A

> class B(var value: A)
defined class B

> new B(new A)
res0: B = B@c8aeb3

> new scala.ref.WeakReference(res0.value)
res1: scala.ref.WeakReference[A] = scala.ref.WeakReferenceWithWrapper@16a5d72

> res0.value = new A

> res1.get // Here I hope to get None
res3: Option[A] = Some(A@135707c)

另一个尝试是由下面的oxbow_lakes。

我也尝试过徒劳地显式运行垃圾收集器（调用java.lang.System.gc）。

有没有办法取消引用res1的内容？

Answer 1

Welcome to Scala version 2.8.1.final (Java HotSpot(TM) 64-Bit Server VM, Java 1.6.0_22).
Type in expressions to have them evaluated.
Type :help for more information.

scala> class A  
defined class A

scala> class B(var value: A)
defined class B

scala> new B(new A)
res0: B = B@4223d9b

scala> new scala.ref.WeakReference(res0.value)
res1: scala.ref.WeakReference[A] = scala.ref.WeakReferenceWithWrapper@20eb607d

scala> res0.value = new A

scala> System gc

scala> res1 get
res3: Option[A] = None

顺便说一下，如果我将它作为没有显式System gc的脚本运行，它也不会删除引用。所以对我而言，这不是REPL的问题，而只是弱引用和垃圾收集器的工作方式。

Answer 2

使用scala -Xprint:parser运行您的代码，即使在重新分配后，您也会看到保留var的旧值。

我将在这里简化一些事情，然后运行两行代码：

var b=1
b=2

这就是Scala打印的内容：

scala> var b=1
[[syntax trees at end of parser]]// Scala source: <console>
package <empty> {
  object line2$object extends scala.ScalaObject {
    def <init>() = {
      super.<init>();
      ()
    };
    object $iw extends scala.ScalaObject {
      def <init>() = {
        super.<init>();
        ()
      };
      object $iw extends scala.ScalaObject {
        def <init>() = {
          super.<init>();
          ()
        };
        var b = 1                                ///// YOUR CODE HERE
      }
    }
  }
}

[[syntax trees at end of parser]]// Scala source: <console>
package <empty> {                                /////THIS IS AN object
                                                 /////SO PRESUMABLY IT CAN'T BE GC'ED
  object RequestResult$line2$object extends scala.ScalaObject {
    def <init>() = {
      super.<init>();
      ()
    };
    lazy val scala_repl_value = {                 /////THIS LAZY VAL
      scala_repl_result;                          /////WILL REFERENCE THE OLD VALUE
      line2$object.$iw.$iw.b                      /////EVEN AFTER YOU REASSIGN THE var
    };
    val scala_repl_result: String = {
      line2$object.$iw.$iw;
      "".$plus("b: Int = ").$plus(scala.runtime.ScalaRunTime.stringOf(line2$object.$iw.$iw.b))
    }
  }
}

b: Int = 1

scala> b=2
[[syntax trees at end of parser]]// Scala source: <console>
package <empty> {
  object line3$object extends scala.ScalaObject {
    def <init>() = {
      super.<init>();
      ()
    };
    object $iw extends scala.ScalaObject {
      def <init>() = {
        super.<init>();
        ()
      };
      import line2$object.$iw.$iw.b;              ///// I DON'T THINK THIS (ORDINARILY ILLEGAL)
                                                  ///// import CONTRIBUTES TO THE PROBLEM
      object $iw extends scala.ScalaObject {
        def <init>() = {
          super.<init>();
          ()
        };
        b = 2;                                    /////YOUR CODE HERE
        val synthvar$0 = b
      }
    }
  }
}

[[syntax trees at end of parser]]// Scala source: <console>
package <empty> {
  object RequestResult$line3$object extends scala.ScalaObject {
    def <init>() = {
      super.<init>();
      ()
    };
    lazy val scala_repl_value = {
      scala_repl_result;
      line3$object.$iw.$iw.synthvar$0
    };
    val scala_repl_result: String = {
      line3$object.$iw.$iw;
      "".$plus("b: Int = ").$plus(line3$object.$iw.$iw.synthvar$0).$plus("\012")
    }
  }
}

b: Int = 2

编辑：要添加到Debilski's answer，我认为以下解决方案可让您根据需要多次重新分配变量，而REPL不会引用旧值：

class A
class B{
   var _value:A = new A
   def value = _value
   def pleaseUpdate( closure: B => Unit ) = closure(this)
}

将容器对象定义为：

val b=new B

每当你想更新里面的变量时：

b.pleaseUpdate( _._value = new A )

Answer 3

我的想法是明确使用var并设置为null：

scala> var b = new B(new A)
b: B = B@45033fb5

scala> new scala.ref.WeakReference(b.value)
res0: scala.ref.WeakReference[A] = scala.ref.WeakReferenceWithWrapper@6a7be687

scala> b = null
b: B = null

scala> res0.get
res1: Option[A] = Some(A@79f71773)

但是，它仍然不起作用：REPL可能是在封面下做的事情，它保留了引用。因此，我不建议用它来测试Reference s的使用。

Answer 4

来自Java API文档：

调用gc方法表明了这一点 Java虚拟机花费精力回收未使用的物品为了使他们记忆目前可以快速占用重用。当控制从中返回时方法调用，Java虚拟机我已尽最大努力收回所有丢弃物体的空间。

在我的轶事经验中，这意味着它很少会触发真正完整的收藏，特别是在可用内存方面没有压力的情况下。如果你对它施加压力，它将被收集。我认为你期望从GC中获得更多的确定性行为。

Welcome to Scala version 2.8.0.final (Java HotSpot(TM) 64-Bit Server VM, Java 1.6.0_22).
Type in expressions to have them evaluated.
Type :help for more information.

scala> var s = new String("Hello, world!")         
s: java.lang.String = Hello, world!

scala> import scala.ref.WeakReference
import scala.ref.WeakReference

scala> val w = new WeakReference(s)  
w: scala.ref.WeakReference[java.lang.String] = scala.ref.WeakReferenceWithWrapper@663f3fbd

scala> s = null
s: java.lang.String = null

scala> Array.ofDim[Byte](1024*1024)
res1: Array[Byte] = Array(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, ...
scala> Array.ofDim[Byte](1024*1024)
res2: Array[Byte] = Array(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, ...
scala> Array.ofDim[Byte](1024*1024)
res3: Array[Byte] = Array(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, ...
scala> Array.ofDim[Byte](1024*1024)
res4: Array[Byte] = Array(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, ...
scala> Array.ofDim[Byte](1024*1024)
res5: Array[Byte] = Array(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, ...
scala> Array.ofDim[Byte](1024*1024)
res6: Array[Byte] = Array(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, ...
scala> System.gc

scala> var g = w.get
g: Option[java.lang.String] = None

WeakReference和Scala REPL

4 个答案: