Question

所以我试图这样做，如果多条件的声明，为了使密码合格，它应该满足5个中的4个。我收到错误说

运营商＆amp;＆amp;未定义参数类型boolean，int

注意：错误发生在我的方法的底部，（如果声明错误）

      public void passRequirments(){


        int digit,symbol,upper,lower;
        int countDigit, countSymbol,countUpper,countLower;
        countDigit = 0;
        countSymbol= 0;
        countUpper = 0;
        countLower = 0;

        for (int i = 0; i < passChar.length; i++){
        digit = (int)passChar[i] ;
        symbol = (int)passChar[i];
        upper  = (int)passChar[i];
        lower  = (int)passChar[i];

        if(digit >=48 && digit <= 57){
          countDigit = 1;
          System.out.println(countDigit);
        }
        else if(symbol >=32 && symbol <= 47 || symbol >=58 && symbol <= 64 ||
                symbol >=91 && symbol <= 96 || symbol >=123 && symbol <= 126){
          countSymbol = 1;
          if (countSymbol == 1){

            System.out.println("hello");
          }
        }
        else if( upper >=65 &&  upper <= 90){
          countUpper = 1;
        }
        else {
          countLower = 1;
        }

 }
         //this is where i'm running into error

        if(passChar.length  >= 8  && countDigit == 1 && countSymbol && countUpper == 1 ||
          passChar.length >= 8 && countDigit == 1 && countSymbol && countLower == 1 ||
          passChar.length >= 8 && countDigit == 1 && countLower  && countUpper == 1 ||
          passChar.length >= 8 && countSymbol == 1 && countLower && countUpper == 1){

       System.out.println("Password Qualfies!");
       passwordScore = passwordScore + 10;

      }
      else {

       System.out.println("Password Doesn't Qualify!");


      }


  }

Answer 1

在java中，if语句中的参数应该是boolean。

我发现您只是为countSymbol检查，而不是根据您的要求countSymbol == 0或countSymbol > 0。

if(passChar.length  >= 8  && countDigit == 1 && countSymbol==0 && countUpper == 1 ||
                                                     ^ change this

在其他Or条件中进行类似的更改

Answer 2

如果按countSymbol && countUpper == 1，您试图说countSymbol 和 countUpper应该等于1，那么&&的工作方式不是countSymbol == 1 && countUpper == 1 。您必须完整地写出两个条件：countLower && countUpper == 1。与node_modules相同。

有趣的事实：如果您使用COBOL编写，那么类似的符号会起作用：）

检查if语句中所有条件的最有效方法是什么？

2 个答案: