Question

我是编程新手，但我已经开始教几个月了。我写了一个猜词游戏程序。该计划做了以下事情：

它从我称之为dictionary的预定义词组中选择一个词。
它解释了游戏规则。
它告诉用户单词中有多少个字母，并用下划线表示每个字母。
它要求用户猜一封信。
它告诉用户猜测是正确的，然后重新打印下划线，但用正确的猜测替换相关的下划线。我的意思是，如果单词是'PYTHON'并且用户猜到'H'，它将打印["_", "_", "_", "H", "_", "_"]。
另一方面，如果猜测不在单词中，它将告诉用户然后重新打印下划线。我的意思是，如果用户的下一个猜测是“Z”，它会说“这封信不在单词中”，然后再次重新打印["_", "_", "_", "H", "_", "_"]，这样用户就可以跟踪他/她的位置。
最后，一旦所有字母都被猜到，它就会祝贺用户并结束游戏。

以下是代码：

import random

dictionary = ("CROWS", "GOAT", "MONKEY", "COW", "HORSE", "SNAKE")
answer = random.choice(dictionary)
answer_length = len(answer)
victory = True
print("""
    I have chosen a word.  Your job is to guess it. I will help you
    keep track.
    """)

print("The word I have chosen is {} letters long.\n".format(answer_length))

underscores = []
for character in answer:
    underscores.append("_")
print(underscores)

while victory:
    guess = input("\nPlease guess a letter: ").strip().capitalize()
    def pos(guess):
        position = 0
        for letter in answer:
            if letter != guess:
                position += 1
            else:
                print("Correct!")
                break
        return position

    def update_board(x):
        global underscores
        if guess in answer:
            underscores[x] = guess
        else:
            print("This letter is not in the word")
        return underscores

    def winner():
        global underscores
        global victory
        if "_" not in underscores:
            print("YOU HAVE WON!")
            victory = False

    x = pos(guess)
    print(update_board(x))
    winner()

现在，我遇到的问题是：程序工作正常，提供计算机从字典中选择的单词中没有任何重复的字母。您会注意到字典中的单词都由唯一字符组成。但是，如果字典中包含单词“CHICKEN”，则程序可能会遇到问题。

想象一下，电脑选择了'CHICKEN'，然后你猜到了字母'C'。该计划将返回：

Correct!
["C", "_", "_", "_", "_", "_", "_"]

此外，如果你再次猜到C，它就会打印

Correct!
["C", "_", "_", "_", "_", "_", "_"]

一次。理想情况下，我想要它做的是在用户第一次猜到'C'时返回["C", "_", "_", "C", "_", "_", "_"]。目前，只有字典中的所有单词都没有任何重复出现的字符时，游戏才能运行。

您可以提供任何帮助，我们将不胜感激。谢谢！

Answer 1

一旦在pos(guess)中找到一个，我们就会停下来检查是否有其他事件发生。因此，您只能获得第一次出现。显然，要解决这个问题，不要在找到东西时停下来。而是每次都完整地完成这个词。

E.g。在pos(guess)中，返回在单词中找到字母的索引列表，并在update_board(x)循环遍历您获得的索引，而不是仅用猜测替换一个下划线。

Answer 2

您可以使用数组来解决它：

import random

dictionary = ("CROWS","CHICKEN")
answer = random.choice(dictionary)
answer_length = len(answer)
victory = True
print("""
    I have chosen a word.  Your job is to guess it. I will help you
    keep track.
    """)

print("The word I have chosen is {} letters long.\n".format(answer_length))

underscores = []
for character in answer:
    underscores.append("_")
print(underscores)
ar=[]
while victory:
    guess = input("\nPlease guess a letter: ").strip().capitalize()
    def pos(guess):
        position = 0
        for letter in answer:
            if letter != guess:
                position += 1
            else:
                print("Correct!")
                ar.append(position)
                position += 1

        return ar

    def update_board(x):
        global underscores
        if guess in answer:
            underscores[x] = guess
        else:
            print("This letter is not in the word")
        return underscores

    def winner():
        global underscores
        global victory
        if "_" not in underscores:
            print("YOU HAVE WON!")
            victory = False

    pos(guess)
    for x in ar:
        print(update_board(x))
    del ar [:]
    winner()

Python - 单词猜谜游戏在重复字符的单词上失败

2 个答案: