Question

背景

我正在尝试在python中编写一个基本的字母游戏。在游戏中，计算机主持人从可能的单词列表中选择一个单词。每个玩家（计算机AI和人类）都会显示一系列空白，每个字母对应一个字母。然后每个玩家猜出一个字母和一个位置，然后告诉其中一个：

那封信属于那个位置（最好的结果）那封信是在这个词中，但不在那个位置那封信不在任何剩余的空白处当单词被完全显示时，正确猜出大多数字母的玩家将赢得一个点。计算机主持人选择另一个单词并重新开始。第一个获得5分的玩家赢得了比赛。在基本游戏中，两个玩家共享他们正在填充的同一组空白，因此玩家可以从彼此的工作中受益。

问题

我正在处理计算机AI部分（代码底部）。我希望它从尚未猜到的字母列表中选择一个随机字母。最好的方法是什么？

import random

#set initial values
player1points= 0
ai= 0
userCorrectLetters= ''
aiCorrectLetters=''
wrongPlace=''
wrongLetters=''
correctLetters = ''
notInWord = ''
endGame = False
alreadyGuessed = 'a'
userGuessPosition = 0

###import wordlist, create mask
with open('/Users/jamyn/Documents/workspace/Lab3/Lab3/wordlist.txt') as wordList:
    secretWord = random.choice(wordList.readlines()).strip()

print (secretWord) 
mask = '_'  * len(secretWord)
for i in range (len(secretWord)):
    if secretWord[i] in correctLetters:
        mask = mask[:i] + secretWord[i] + mask [i+1:]
for letter in mask:
    print (letter, end='')
    print ()

print ()


def addAlreadyGuessed():
    alreadyGuessed= userCorrectLetters + aiCorrectLetters + wrongLetters + correctLetters

def displayGame():
    print ('letters are in word but not in correct location:', wrongPlace)
    print ('letters not in word:', notInWord)
    ##asks the user for a guess, assigns input to variable
def getUserGuess(alreadyGuessed):


    while True:
        print ('enter your letter')
        userGuess = input ()
        userGuess= userGuess.lower()
        if len(userGuess) != 1:
            print ('please enter only one letter')
        elif userGuess in alreadyGuessed:
            print ('that letter has already been guessed. try again')
        elif userGuess not in 'abcdefjhijklmnopqrstuvwxyz':
            print ('only letters are acceptable guesses. try again.')
        else:
            return userGuess

def newGame():
    print ('yay. that was great. do you want to play again? answer yes or no.')
    return input().lower().startswith('y')


userTurn=True     
while userTurn == True:
    print ('which character place would you like to guess. Enter number?')
    userGuessPosition = int(input())

    slice1 = userGuessPosition - 1  
    print (secretWord)  


    ##player types in letter
    guess = getUserGuess(wrongLetters + correctLetters)
    if guess== (secretWord[slice1:userGuessPosition]):
        correctLetters = correctLetters + guess
        print ('you got it right! ')
        break
    elif guess in secretWord:
            userCorrectLetters = userCorrectLetters + guess 
            correctLetters = correctLetters + guess
            print ('that letter is in the word, but not in that position')
            break
    else:
            wrongLetters = wrongLetters + guess
            print ('nope. that letter is not in the word')
            break

print ('its the computers turn')

aiTurn=True

while aiTurn == True:
    aiGuess=random.choice('abcdefghijklmnopqrstuvwxyz')
    print (aiGuess)

Answer 1

使用pythons set，保留一个包含所有26个字母的集合，以及一组猜测的集合，并且只询问大集合中不在较大集合http://docs.python.org/2/library/sets.html中的元素...然后拉你从该结果中随机选择

allletters = set(list('abcdefghijklmnopqrstuvwxyz'))
usedletters = set() # update this as you go
availletters = allletters.difference(usedletters) #s - t    new set with elements in s but not in t

很好地打印出来，你可以做到

print sorted(availletters)

或

print ', '.join(sorted(availletters))

回答关于添加猜测的后续内容，这是一个简单的例子

allletters = set(list('abcdefghijklmnopqrstuvwxyz'))
usedletters = set() # update this as you go
while( len(usedletters) != len(allletters) ):
    guessedletter = raw_input("pick a letter")
    availletters = allletters.difference(usedletters)
    usedletters.update(guessedletter)

你也可以只有一个列表并减去他们猜到的字母，例如：

allletters = set(list('abcdefghijklmnopqrstuvwxyz'))
while( len(usedletters) != len(allletters) ):
    guessedletter = raw_input("pick a letter")
    allletters.difference_update(guessedletter)

python中的字母/单词猜谜游戏

1 个答案: