我写过一个简单的相关函数，它接受三个变量。 ＆＃34; A＆＃34;和＆＃34; B＆＃34;是等长的数值向量，＆＃34; n＆＃34;是长度。
Corr.fxn <- function(A, B, n){
Correlation <- (sum((A - mean(A))*(B - mean(B))) / (n-1)) / (sd(A)*sd(B))
return(Correlation)
}
该功能运行良好，但我有许多我想要处理的向量。修改此代码以处理所有＆＃34; N取2＆＃34;的最佳方法是什么？对我的矢量＆＃34; N＆＃34;？
的独特分析编辑：
显示载体结构的示例数据：
A <- c(-1, 0, 1, -1, 0, 1, -1, 0, 1)
B <- c(1, 1, -1, 0, 1, -1, 0, 0, 1)
...
n <- length(A)
所以，让我说我有矢量A到Z，我想修改我的代码，输出一个包含所有{26取2}相关值的新矢量。
答案 0 :(得分：1)
假设列表v中有一堆数字向量，可以采用以下一种方法来执行此操作：
v <- list()
for (i in 1:10) {
v[[i]] <- sample(1:10, 10, replace = TRUE)
}
apply(combn(1:10, 2), 2, function(x) Corr.fxn(v[[x[1]]], v[[x[2]]], length(v[[x[1]]])))
答案 1 :(得分：0)
在这个答案中，我假设有两件事。首先，您想自己编写一个函数，否则您可以使用import random
def randIntArray():
randomList = []
randomList = random.sample(range(1, 101), 10)
return randomList
def getInt(prompt):
# Function to call when asking for the A and B values later.
try:
x = input(prompt)
y = int(x)
return y
except:
print("That was not an integer. Please enter an integer. ")
def getData():
userIntList = []
for i in range(10):
userNum = getInt("Please enter value number : ")
userIntList.append(userNum)
return userIntList
def swap(a, j, k):
temp1 = a[j]
a[j] = a[k]
a[k] = temp1
def sortArray(a):
for i in range(len(a)):
for k in range(len(a) - 1):
first = k
second = k + 1
if (a[first] > a[second]):
# Uses Swap function
swap(a, first, second)
def displayArray(theArray):
outList = theArray
return outList
def maxValue(theArray):
maxNum = 0
for i in theArray:
if i > maxNum:
maxNum = i
return maxNum
def minValue(theArray):
minNum = theArray[0]
for i in theArray:
if i < minNum:
minNum = i
return minNum
def totalValue(theArray):
aTotal = 0
for s in theArray:
aTotal += s
return aTotal
def aveValue(theArray):
aTotal = totalValue(theArray)
aAverage = aTotal / len(theArray)
return aAverage
def dataOut(theArray):
print("The maximum value is: " + str(maxValue(theArray)))
print("The minimum value is: " + str(minValue(theArray)))
print("The total value is: " + str(totalValue(theArray)))
print("The average value is: " + str(aveValue(theArray)) + "\n")
def processInput(theArray):
print("The original array was:\n " + str(displayArray(theArray)) + "\n")
dataOut(theArray)
sortArray(theArray)
print("The sorted array is:\n " + str(displayArray(theArray)))
def unitTest():
print("Running test . . .")
randIntArray()
theArray = randIntArray()
processInput(theArray)
print("\n Finished test . . .")
def main():
unitTest()
theArray = []
done = False
while not done:
proceedQ = input("Would you like to enter 10 numbers <y/n>? ")
if proceedQ == "y":
getData()
processInput(theArray)
if proceedQ != "y":
done = True
main()
。其次，你想要＆＃34; N取2＆＃34;部分在函数内部，否则前面建议的方法是正确的。在这种情况下，您可以这样做：
Hmisc::rcorr以Corr.fxn <- function(vectors, n){
pairs<- combn(length(vectors), 2)
npairs<- ncol(pairs)
cor.mat<- matrix(NA, nrow = length(vectors), ncol = npairs)
for (i in 1:ncol(pairs)){
A<- vectors[[pairs[1, i]]]
B<- vectors[[pairs[2, i]]]
cor.mat[pairs[1, i], pairs[2, i]] <- (sum((A - mean(A))*(B - mean(B))) / (n-1)) /(sd(A)*sd(B))
}
cor.mat[lower.tri(cor.mat)]<- cor.mat[upper.tri(cor.mat)] ###
diag(cor.mat)<- 1 ###
cor.mat<- data.frame(cor.mat) ###
row.names(cor.mat)<- colnames(cor.mat)<- names(vectors) ###
return(cor.mat)
}
结尾的行是出于装饰原因。主要输入是一个名为＆＃34; vectors＆＃34;的列表。所以它的工作原理如下：
###