我使用包含messages作为键的字典和
ValueError: If using all scalar values, you must pass an index作为值。它循环遍历第一个数据帧，对于每个问题，将第一条消息发布为目的地的商店，将第二条消息作为源发布的商店，在关键“源 - 目的地”的字典中添加计数器。
现在我正在尝试将字典转换为数据帧，但是我收到此错误消息
import pandas as pd
from itertools import permutations
df = pd.read_csv('example.csv', sep=';', engine='python')
messages = {} # the dictionary where results is going to be stored
student= set()
destination = False # a simple boolean to make sure message 2 follows message 1
for row in df: # iterate over the dataframe
student.add(row[2]) # collect students' name
if row[1] == 1: # if it is an initial message
destination = row[2] # we store students as destination
elif row[1] == 2 and destination: # if this is a second message
source = row[2] # store student as source
key = source + "-" + destination # construct a key based on source/destination
if key not in messages: # if the key is new to dictionary
messages[key] = 1 # create the new entry
else: # otherwise
messages[key] += 1 # add a counter to the existing entry
destination = False # reset destination
else:
destination = False # reset destination
# add the pairs of source-destination who didn't interact in the dictionnary
for pair in permutations(student, 2):
if "-".join(pair) not in messages:
messages["-".join(pair)] = 0
f1 = pd.DataFrame.from_dict(messages)
print(f1)
。
{{1}}
知道为什么吗？
提前谢谢。
答案 0 :(得分：1)
您可能在代码中的选项卡和空格之间混合使用。 尝试删除所有选项卡并用空格替换它们。
同样的问题：IndentationError: unindent does not match any outer indentation level