Question

我有错误当我填写表格并单击提交结果是错误“Data Gagal Di tambahkan” 这里是代码

<?php
include 'koneksi/koneksi.php';

if ($_SERVER['REQUEST_METHOD'] == "POST"){
$nis                    = $_POST['nis'];
$nama                   = $_POST['nama'];
$kelas                  = $_POST['kelas'];
$nilai_ulangan_teori    = $_POST['nilai_ulangan_teori'];
$nilai_ulangan_praktek  = $_POST['nilai_ulangan_praktek'];

$sql    = "INSERT INTO t_siswa VALUES ('$nis',
        '$nama',
        '$kelas',
        '$nilai_ulangan_teori',
        '$nilai_ulangan_praktek'
        )";
$nilai  ="($nilai_ulangan_teori + $nilai_ulangan_praktek)/2";
if (mysql_query($sql)){
    header("location:index.php");
} else {
    echo'<script type="text/javascript">alert("Data gagal ditambahkan");</script>';
}
}

此处为连接

<?php
$host = "localhost";
$username = "root";
$password = "";
$db = "db_uas_pwd_2017";

mysql_connect($host, $username, $password) or die (mysql_error());
mysql_select_db($db);

$mysqli = mysql_connect($host, $username, $password, $db);

Answer 1

您的SQL代码错误。您需要在SQL代码中指定列名称。例如，SQL应该看起来像这样

INSERT INTO table_name (column1, column2, column3,...) VALUES (value1, value2, value3,...)

并且，mysql_已被折旧，现在PHP建议使用mysqli_或PDO。有关更多参考资料，请访问以下链接：

来自xXAlphaManXx的答案，15岁

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