Question

有谁能告诉我for - 循环中发生了什么？

    %find slopes of each line
    m1 = diff(line1_start_end_points(:,2))/ diff(line1_start_end_points(:,1))+0.1/(2*pi);
    m2 = diff(line2_start_end_points(:,2))/ diff(line2_start_end_points(:,1))+0.1/(2*pi);
    m3 = diff(line3_start_end_points(:,2))/ diff(line3_start_end_points(:,1))+0.1/(2*pi);

    %====================find longest scratch on each line==========================
    if (line1_flag==0)
        x = line1_start_end_points(1,1);
        y = line1_start_end_points(1,2); 
        % iterate through the height of the image
        for i=1:COLS                               
            final_line1(:,i)=[y + m1*(i-x)           i]';
            gray_image_copy1(floor(y+m1*(i-x)), i) = 255;
            hough_in_new1(:,i)=0;
            hough_in_new1(floor(y+m1*(i-x)),i)=1;
        end
    end

.... .... ....
.... .... ....

Answer 1

似乎是在灰度图像和零数组上逐个像素地绘制直线：

if (line1_flag==0)
    % x coordinate of line start
    x = line1_start_end_points(1,1); 
    % y coordinate of line start
    y = line1_start_end_points(1,2);
    % iterate through the height of the image
    for i=1:COLS % iterate on image columns (x's), i is like variable x
        % compute the y value for this column using y = mx + b, where
        % (i) is the x coordinte, and j=(y + m1*(i-x)) is the y coord.
        j = y + m1*(i-x);
        final_line1(:,i)=[j i]';
        % draw this x-y pixel in white on the image, floor j to nearest
        % integer - results in 255's where the line is
        gray_image_copy1(floor(j), i) = 255;
        % reset all hough array i'th column
        hough_in_new1(:,i)=0;
        % set only the j,i element to 1 - results in 1's where the line
        % is
        hough_in_new1(floor(j),i)=1;
    end
end

MATLAB代码说明

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