Question

我正在使用asp.net（C＃）网站，我希望使用Deserialize类XML XmlSerializer字符串。

我的模型（.cs文件）

[XmlRoot("MedicalClearanceFormRoot")]
  public class MedicalClearanceViewModel
  {


    [XmlAttribute("PassengerName")]
    public string PassengerName { get; set; }

    [XmlAttribute("Gender")]
    public string Gender { get; set; }

    [XmlAttribute("Age")]
    public string Age { get; set; }

    [XmlAttribute("PhoneNo")]
    public string PhoneNo { get; set; }

    [XmlAttribute("Email")]
    public string Email { get; set; }

    [XmlAttribute("BookingRefNo")]
    public string BookingRefNo { get; set; } 
}

XML字符串

<MedicalClearanceFormRoot>
  <MedicalClearanceForm PassengerName="AAAAAAAAAAAAA" Age="11" PhoneNo="TTTTTTTTTTT" Email="ZZZZZZZZZZZZZZZZZZZ" BookingRefNo="11111111111111111111" />  
</MedicalClearanceFormRoot>

将XML反序列化为对象的代码

string myXMLStringFromDB = GetXMLStringFromDb(); // this method will return XML from db.

    XmlSerializer serializer = new XmlSerializer(typeof(MedicalClearanceViewModel));
              using (TextReader reader = new StringReader(myXMLStringFromDB))
              {
               MedicalClearanceViewModel objModel = (MedicalClearanceViewModel)serializer.Deserialize(reader);
              }

但问题是，当我使用上面的代码将XML反序列化为对象时... PassengerName，Age，PhoneNo等属性在{ {1}}

有人可以帮助我在我的班级上设置正确的XML符号，有人可以帮我解决这个问题。

任何帮助将受到高度赞赏！谢谢

Answer 1

我创建了一个示例，代码将完全如下所示。你的模型不正确。

 public class MedicalClearanceForm
{
    [XmlAttribute("PassengerName")]
    public string PassengerName { get; set; }

    [XmlAttribute("Gender")]
    public string Gender { get; set; }

    [XmlAttribute("Age")]
    public string Age { get; set; }

    [XmlAttribute("PhoneNo")]
    public string PhoneNo { get; set; }

    [XmlAttribute("Email")]
    public string Email { get; set; }

    [XmlAttribute("BookingRefNo")]
    public string BookingRefNo { get; set; }
}
[XmlRoot("MedicalClearanceFormRoot")]
public class MedicalClearanceFormRoot
{


    [XmlElement("MedicalClearanceForm")]
    public MedicalClearanceForm MedicalClearanceForm { get; set; }


}
class Program
{
    static void Main(string[] args)
    {
        string myXMLStringFromDB = @"<MedicalClearanceFormRoot><MedicalClearanceForm PassengerName = 'AAAAAAAAAAAAA' Age = '11' PhoneNo = 'TTTTTTTTTTT' Email = 'ZZZZZZZZZZZZZZZZZZZ' BookingRefNo = '11111111111111111111' /></MedicalClearanceFormRoot >";

        XmlSerializer serializer = new XmlSerializer(typeof(MedicalClearanceFormRoot));
        using (TextReader reader = new StringReader(myXMLStringFromDB))
        {
            MedicalClearanceFormRoot objModel = (MedicalClearanceFormRoot)serializer.Deserialize(reader);
        }

    }
}

Answer 2

为了满足指定的XML，我相信你需要这个类结构。

[XmlRoot("MedicalClearanceFormRoot")]
public class MedicalClearanceViewModel
{
    public MedicalClearanceFormElement MedicalClearanceForm { get; set; }
}

[XmlElement]
public class MedicalClearanceFormElement
{
    [XmlAttribute("PassengerName")]
    public string PassengerName { get; set; }

    [XmlAttribute("Gender")]
    public string Gender { get; set; }

    [XmlAttribute("Age")]
    public string Age { get; set; }

    [XmlAttribute("PhoneNo")]
    public string PhoneNo { get; set; }

    [XmlAttribute("Email")]
    public string Email { get; set; }

    [XmlAttribute("BookingRefNo")]
    public string BookingRefNo { get; set; } 
}

在C＃XmlRoot中将XML反序列化为对象不起作用

2 个答案: