Question

我正在使用以下代码，其中我正在尝试序列化和取消对StringResource类的对象。请注意Resource1.stringXml =它来自资源文件。如果我通过strelemet.outerXMl我从Deserialize对象获取对象，但如果我传递Resource1.stringXml我得到以下异常

{“＆lt; STRING xmlns =''＆gt;不是预期的。”} System.Exception {System.InvalidOperationException}

 class Program
{
    static void Main(string[] args)
    {

        StringResource str = new StringResource();
        str.DELETE = "CanDelete";
        str.ID= "23342";
        XmlElement strelemet = SerializeObjectToXmlNode (str);

        StringResource strResourceObject = DeSerializeXmlNodeToObject<StringResource>(Resource1.stringXml);
        Console.ReadLine();

    }
    public static T DeSerializeXmlNodeToObject<T>(string objectNodeOuterXml)
    {
        try
        {
            TextReader objStringsTextReader = new StringReader(objectNodeOuterXml);
            XmlSerializer stringResourceSerializer = new XmlSerializer(typeof(T),string.Empty);
            return (T)stringResourceSerializer.Deserialize(objStringsTextReader);
        }
        catch (Exception excep)
        {
            return default(T);
        }
    }

    public static XmlElement SerializeObjectToXmlNode(object obj)
    {
        using (MemoryStream memoryStream = new MemoryStream())
        {
            try
            {
                XmlSerializerNamespaces xmlNameSpace = new XmlSerializerNamespaces();
                xmlNameSpace.Add(string.Empty, string.Empty);
                XmlWriterSettings writerSettings = new XmlWriterSettings();
                writerSettings.CloseOutput = false;
                writerSettings.Encoding = System.Text.Encoding.UTF8;
                writerSettings.Indent = false;

                writerSettings.OmitXmlDeclaration = true;

                XmlWriter writer = XmlWriter.Create(memoryStream, writerSettings);

                XmlSerializer xmlserializer = new XmlSerializer(obj.GetType());
                xmlserializer.Serialize(writer, obj, xmlNameSpace);
                writer.Close();
                memoryStream.Position = 0;
                XmlDocument serializeObjectDoc = new XmlDocument();
                serializeObjectDoc.Load(memoryStream);

                return serializeObjectDoc.DocumentElement;
            }
            catch (Exception excep)
            {
                return null;
            }
        }
    }
}
public class StringResource
{
    [XmlAttribute]
    public string DELETE;
    [XmlAttribute]
    public string ID;
}

＆LT; STRING ID =“1”DELETE =“True”/＆gt;

Answer 1

问题是XML根节点和类

中的名称不匹配

< STRING ID="1" DELETE="True" />  -- STRING here
public class StringResource       -- StringResource Here.

将 xmlroot 属性添加到您的班级，并看看会发生什么

[XmlRoot( "STRING " )]
public class StringResource 
{ 
    [XmlAttribute] 
    public string DELETE; 
    [XmlAttribute] 
    public string ID; 
}

Answer 2

显而易见Resource1.stringXml不包含可以反序列化为StringResource对象的正确XML。 XML应如下所示：

<StringResource DELETE="CanDelete" ID="23342" />

无法将xml反序列化为对象

2 个答案: