Rails如何从ActiveRecord对象中仅提取(并复制)某些属性?

时间:2017-05-08 01:57:55

标签: ruby-on-rails ruby activerecord

在Rails 5中,我想创建一个Author模型的新实例,但在这个过程中我只想从我的User模型中复制属性值(列)的一个子集。

我正在尝试运行以下代码:

user = User.first
Author.create user.attributes.without("id", "token", "secret", "created_at", "updated_at", "active", "email", "encrypted_password", "first_name", "last_name", "reset_password_token", "reset_password_sent_at", "remember_created_at", "sign_in_count", "current_sign_in_at", "last_sign_in_at", "current_sign_in_ip", "last_sign_in_ip")

User.first方法工作并从表中返回有效用户。但是,Author.create行不起作用。我得到一个NoMethodError:未定义的方法`每个'为nil:NilClass错误。

这是schema.rb文件中的User表:

create_table "users", force: :cascade do |t|
    t.string   "provider",                               null: false
    t.string   "uid",                                    null: false
    t.string   "name"
    t.string   "location"
    t.string   "image_url"
    t.string   "url"
    t.string   "token"
    t.string   "secret"
    t.datetime "created_at",                             null: false
    t.datetime "updated_at",                             null: false
    t.boolean  "active",                 default: false
    t.text     "description"
    t.string   "screen_name"
    t.integer  "followers"
    t.integer  "following"
    t.integer  "statuses"
    t.integer  "listed"
    t.integer  "lists"
    t.integer  "favorites"
    t.integer  "views",                  default: 0
    t.string   "website"
    t.string   "email",                  default: "",    null: false
    t.string   "encrypted_password",     default: "",    null: false
    t.string   "first_name",             default: "",    null: false
    t.string   "last_name",              default: "",    null: false
    t.string   "reset_password_token"
    t.datetime "reset_password_sent_at"
    t.datetime "remember_created_at"
    t.integer  "sign_in_count",          default: 0,     null: false
    t.datetime "current_sign_in_at"
    t.datetime "last_sign_in_at"
    t.inet     "current_sign_in_ip"
    t.inet     "last_sign_in_ip"
    t.index ["active"], name: "index_users_on_active", using: :btree
    t.index ["email"], name: "index_users_on_email", unique: true, using: :btree
    t.index ["provider", "uid"], name: "index_users_on_provider_and_uid", unique: true, using: :btree
    t.index ["provider"], name: "index_users_on_provider", using: :btree
    t.index ["uid"], name: "index_users_on_uid", using: :btree
end

这是我的作者表:

create_table "authors", force: :cascade do |t|
    t.string   "uid",                     null: false
    t.string   "provider",                null: false
    t.string   "name"
    t.string   "location"
    t.string   "image_url"
    t.string   "url"
    t.text     "description"
    t.string   "screen_name"
    t.integer  "followers",   default: 0
    t.integer  "following",   default: 0
    t.integer  "statuses",    default: 0
    t.integer  "listed",      default: 0
    t.integer  "lists",       default: 0
    t.integer  "favorites",   default: 0
    t.integer  "views",       default: 0
    t.string   "website"
    t.datetime "created_at",              null: false
    t.datetime "updated_at",              null: false
    t.index ["provider"], name: "index_authors_on_provider", using: :btree
    t.index ["uid", "provider"], name: "index_authors_on_uid_and_provider", unique: true, using: :btree
    t.index ["uid"], name: "index_authors_on_uid", using: :btree
end

如您所见,新的Author表具有许多与User表相同的列/属性,但我只想在创建新的Author对象时复制User属性的一个子集(列和值)。

也许user.attributes.without方法不正确?

0 个答案:

没有答案