Question

我在laravel中有一个函数用于将数据保存到数据库中，由于某种原因，其中一个变量不会添加到数据库中，特别是日历的id。我已经尝试在数据库条目之前和之后返回变量，并且它在两次都存在，它只是不会被添加。以下是我到目前为止的情况：

from multiprocessing import Pool, cpu_count
from functools import partial


def updatePheromone(listOfDicts):
    # Graph is accesible within this function's scope

    pool = Pool()
    partial_Func = partial(processDict, graph=graph)
    pool.map_async(partial_Func, listOfDicts, len(listOfDicts)/cpu_count())
    pool.close()

所有其他数据都已正确添加到数据库中，class SetupPhotoshoot{ public function createListing(Request $request){ $calendarAdd = $this->addToCalendar($request); $addtoDB = $this->addToDB($request, $calendarAdd['id']); return $addtoDB; } protected function addToDB($request, $calendarID){ //Some code here return $calendarID; //This is to see if the id exists inside the function, which it does. $newSchedule = new Schedule; $addtoDB = $newSchedule->create({ //Add a bunch of fields 'services_id' => $request->Package, 'appt_time' => $request->DateTime, 'total' => $request->total, 'calendar_id' => $calendarID //This is where I want the id to be added, but it isn't working. }); return $calendarID; //I tried returning after adding to DB to see if it somehow got lost between before adding to DB and after, but it still returned. //NOTE: the two individual returns were NOT used at the same time. I commented out one to test if the other returned, so it IS NOT because I used return multiple times. } }除了它所说的特定错误＆＃34;一般错误：1364字段＆＃39; calendar_id＆＃39;没有默认值。＆＃34;当我允许空值时，它只添加＆＃34; null＆＃34;作为数据库中的值。这是它在数据库中的样子（这是MYSQL）：

calendar_id.

Answer 1

'calendar_id'没有默认值

$calendarID未被传递，可能为null，请使用dd($calendarID)确保设置。

create()也是一个静态方法，所以不要创建Schedule的实例你可以静态地称呼Schedule::create($data)。

在您的模型上，确保calendar_id是您的可填充数组的一部分：

protected $fillable = [
     'services_id',
     'appt_time',
     'total',
     'calendar_id'
];

传递给函数的laravel值不会传递到数据库中

1 个答案: