我正在尝试制作一个FSM,根据按下的按钮打开LED矩阵上的不同LED。但是,LED不会保持打开状态,释放按钮后,第一个LED会再次亮起。 这是代码:
module OneLed( input logic clk, reset, input logic [1:0] button,
output logic [7:0] rows,
output logic shcp, stcp, mr, oe, ds); //The LED matrix has 3 74hc595 shift registers below it
logic [7:0] [23:0] in;
logic [1:0] butreg; // thought a register would remember the button input
assign butreg = button;
//FSM
typedef enum logic [1:0] {S0, S1, S2} statetype;
statetype state , nextstate;
//state register
always_ff @(posedge clk, posedge reset)
if (reset) state <= S0;
else state <= nextstate;
//next state logic
always_comb
case(butreg)
S0: if (2'b01) nextstate = S1;
else if (2'b10) nextstate = S2;
else nextstate = S0;
S1: if (2'b01) nextstate = S2;
else if (2'b10) nextstate = S0;
else nextstate = S1;
S2: if (2'b01) nextstate = S0;
else if (2'b10) nextstate = S1;
else nextstate = S2;
default: nextstate = S0;
endcase
//output logic
always_comb
begin
if (state == S0)
in [0] = 24'b10000000_00000000_00000000;
else if (state == S1)
in [0] = 24'b00000000_10000000_00000000;
else if (state == S2)
in[0] = 24'b00000000_00000000_10000000;
end
led LED ( clk, in , rows, shcp, stcp, mr, oe, ds); // this module works fine
endmodule
答案 0 :(得分:0)
assign butreg = button;
此声明将 butreg 视为电线,直接连接到输入信号按钮。
如果您想将按钮的值锁定到 butreg 寄存器中,则需要使用始终块并触发适当的事件(posedge clk或*或其他一些条件。
例如,您可以使用
代替上述分配always @(posedge clk) begin
if (button == 2'b00) begin
butreg <= butreg;
end
else begin
butreg <= button;
end
end