Question

我想知道如何使用SQL获得所需的结果集，并且我已经过度思考了这个问题，并且此时不能为树林寻找树木。

我所拥有的是一个自引用员工表（empID，MgrID，empUserName，更多......）我有一个缺陷表，它有一堆缺陷，使用empUserName字段与employees表相关联。

我想要一个带有empID参数的报告，并获取分配给它们的所有缺陷，以及所有参数的直接报告（所以员工.mgrID = @ empid传入的地方）

现在这里是棘手的部分 - 直接报告可能在层次结构中有自己的直接报告，这些缺陷需要汇总并添加到1级用户的缺陷数量中。这是什么让我感到困惑，对此有任何想法？一些伪代码可以很好地遵循如何完成的逻辑

谢谢大家！

Answer 1

alter PROC sel_DefectReportByManagerNTID_rollup
(@ManagerNTID NVARCHAR(100))    
AS

CREATE TABLE #DefectCounts
(
id INT IDENTITY(1, 1) ,
MgrRolledInto NVARCHAR(100) NULL,
AltBusinessSeverity NVARCHAR(100) NULL,
DefectCount INT NULL
);


CREATE TABLE #directReports
(
pk INT IDENTITY(1, 1) ,
directReportNTID NVARCHAR(100) NULL
);

INSERT INTO #directReports
SELECT NTID FROM Employees WHERE ManagerNTID = @ManagerNTID
--select * from #directReports

DECLARE @maxPK INT;
SELECT @maxPK = MAX(PK) FROM #directReports

DECLARE @pk INT;
SET @pk = 1


INSERT INTO #DefectCounts (MgrRolledInto,AltBusinessSeverity,DefectCount)
SELECT @ManagerNTID, d.AltBusinessSeverity, COUNT(*)
        FROM Defects d
            JOIN StatusCode C ON C.CodeName = d.Status AND c.scid = 10
        WHERE d.AssignedTo = @ManagerNTID
        GROUP BY d.AltBusinessSeverity


WHILE @pk <= @maxPK
BEGIN
    /* Get one direct report at a time to aggregate their defects under them... */
    DECLARE @dirRptNTID NVARCHAR(100);
    SET @dirRptNTID = (SELECT directReportNTID
                        FROM #directReports
                        WHERE PK = @pk)


    INSERT INTO #DefectCounts (MgrRolledInto,AltBusinessSeverity,DefectCount)
        SELECT @dirRptNTID, d.AltBusinessSeverity, COUNT(*)
        FROM Defects d
            JOIN StatusCode C ON C.CodeName = d.Status AND c.scid = 10
            JOIN (SELECT * FROM fnGetEmployeeHierarchyByUsername(@dirRptNTID) ) emp ON emp.NTID = d.AssignedTo
        WHERE d.AssignedTo IS NOT NULL
        GROUP BY d.AltBusinessSeverity

    SELECT @pk = @pk + 1
END



SELECT  e.FullName,     
  isnull(Urgent,0) as Urgent,     
  isnull(High,0) as High,     
  isnull(Medium,0) as Medium,    
  isnull(Medium3000,0) as Medium3000,    
  isnull(Low,0) as Low    
FROM (  select * from fnGetEmployeeHierarchyByUsername (@ManagerNTID) where depth <= 1) e    
left outer join (
                    SELECT  MgrRolledInto,    
                            SUM([1-Urgent]) AS Urgent,    
                            SUM([2-High]) AS High,    
                            SUM([3-Medium]) AS Medium,    
                            SUM([3-Medium (3000)]) AS Medium3000,  
                            SUM([4-Low]) AS Low    
                    FROM #DefectCounts dfs
                    PIVOT 
                    (sum(DefectCount) FOR AltBusinessSeverity IN ([1-Urgent],[2-High],[3-Medium],[3-Medium (3000)],[4-Low])) V    
                    GROUP BY MgrRolledInto
                ) def_data on def_data.MgrRolledInto = e.NTID
order by e.depth

sql专业人员需要解决逻辑问题

1 个答案: