使用比较运算符创建新的DataFrame列

Question

我有一个类似于此的DataFrame：

while ($token != null) {
    require 'ListInboundShipmentsByNextToken.php';
    $request->setNextToken($token);
    echo print_r($request);

    // Create new XML document.
    $shipmentXML = invokeListInboundShipmentsByNextToken($service, $request);
    $shipments = new SimpleXMLElement($shipmentXML);

    // Use XML document to create array of all shipments.
    foreach ($shipments->ListInboundShipmentsResult->ShipmentData->member as $member) {
        $shipmentArray[] = array(
            "ShipmentId"=>$member->ShipmentId,
            "ShipmentStatus"=>$member->ShipmentStatus
        );
    }
    $token = $shipments->ListInboundShipmentsResult->NextToken;
}

我想使用两个比较运算符添加一列。像这样：

    0
0   3
1  11
2   7
3  15

我希望我的回报看起来像这样：

df[1] = np.where(df[1]<= 10,1 & df[1]>10,0)

但是，我收到此错误消息：

    0   1
0   3   1
1  11   0
2   7   1
3  15   0

任何帮助将不胜感激！

Answer 1

<强>设置

SELECT
  DISTINCT DETAIL.DETAIL_ITEM_NUM,
  Max(DETAIL.DETAIL_RECD_DATE) AS MaxOfDETAIL_RECD_DATE
FROM HEADER 
INNER JOIN 
  DETAIL ON HEADER.HEADER_PO_NUM = DETAIL.DETAIL_PO_NUM
GROUP BY DETAIL.DETAIL_ITEM_NUM;

<强>解决方案

df = pd.DataFrame({'0': {0: 3, 1: 11, 2: 7, 3: 15}})
Out[1292]: 
    0
0   3
1  11
2   7
3  15