Question

我使用$("form").serialize()提交表单数据。虽然我从一个方法返回值它工作正常。我的方法代码如下。

 public function store(Request $request)
 {
    $list = @$request['lists'];
    $total_amount = @$request->total_amount;
    $r_g_amount = @$request->r_g_amount;
    $type = @$request->type;
    $cash = @$request->cash;
    $credit = @$request->credit;
    $bank = @$request->bank;
    $from = @$request->from;
    $to = @$request->to;
    return $cash;
  }

它向我发送空值，如果我return $request->formdata那么它会向我发送表格的所有细节。 formdata是变量，我从ajax传递为formdata:$("form").serialize()。

那么如何将表单数据的值转换为variable。

ajax请求

 $.ajax({
    url: "{{ route('HK.store') }}",
    data: {
       lists: list, total_amount: total_amount, formdata : $("form").serialize(), "_token": "{{ csrf_token() }}"
    },
    type: "POST",
    success: function (data) {
    console.log(data);
    }
 });

enter code here

Answer 1

在Laravel的控制器功能中使用以下代码，

    $box = $request->all();        
    $myValue=  array();
    parse_str($box['formdata'], $myValue);
    print_r($myValue);

希望它会对你有所帮助！

Answer 2

当您使用动态发布数据时，您必须确保存在变量。以下是如何获取所需变量的示例：

<meta name="viewport" content="width=device-width">

Answer 3

您需要更新代码，如：

public function store(Request $request)
 {
    $list = $request->lists;
    $total_amount = $request->total_amount;
    $r_g_amount = $request->r_g_amount;
    $type = $request->type;
    $cash = $request->cash;
    $credit = $request->credit;
    $bank = $request->bank;
    $from = $request->from;
    $to = $request->to;

   return response(['cash' => $cash]);
  }

Answer 4

您可以先将序列化的 formData 转换为 Object，然后将其发送到您的服务器：

const clientInfo= $('#checkoutForm').serialize();
const searchParams = new URLSearchParams(clientInfo);
clientInfo = Object.fromEntries(searchParams);// { 'type' => 'listing', 'page' => '2', 'rowCount' => '10' }

然后在 ajax 请求中，将 clientInfo 传递给 data 属性：

$.ajax({
  url: ...,
  method: "post",
  data: clientInfo ,
  success: function(){

 }
})

在控制器中，当你添加有效载荷时，它看起来像这样：

array:6 [
  "customer_name" => "Arely Torphy II"
  "customer_email" => "lexi.kulas@jacobson.net"
  "customer_phone" => "1-448-897-3923 x1937"
  "address" => "1422 Ellie Stream Suite 859"
  "post" => "37167"
  "company_name" => "company"
]

现在，您可以轻松检索您想要的任何数据。

如何在laravel控制器中检索form.serialize（）数据

4 个答案: