如何在laravel雄辩中从多个表中检索数据

时间:2017-05-17 07:52:54

标签: laravel laravel-5 laravel-5.2 laravel-5.3 laravel-eloquent

Model relation
---------------------
language.php
----
public function attributeDetail()
{
    return $this->hasMany(AttributeDetail::class, 'language_id');
}

attribute.php
----
public function attributeDetail()
{
    return $this->hasMany(AttributeDetail::class, 'attribute_id');
}

attributeDetail.php
----
public function language()
{
    return $this->belongsTo(Language::class);
}
public function attribute()
{
    return $this->belongsTo(Attribute::class);
}

我想像这样显示json对象

{
  'attribute_id' => 101,
  'available_language' => [
    {'id' => 1,'language_name' => 'English'},
    {'id' => 2,'language_name' => 'French'}
  ],
}

表格结构:

languages(`id`, `language_name`, `translate_version`, `is_default`, `status`);
attributes(`id`, `required`, `type`, `status`);
attributedetails(id`, `attribute_id`, `language_id`, `attribute_name`, `status`);

1 个答案:

答案 0 :(得分:2)

尝试这样的事,

$results =  Attribute::select('id')->with(['attributeDetail.language' => function ($query) {
    $query->select('id', 'language_name');
}])->get();