Question

如何在不使用Union的情况下获取页脚部分的人数总和。任何人都可以提供一些想法

SELECT DeptID, COUNT(EmpID) AS TotalHeadCount  FROM EmployeeDetails          
WHERE (datepart(yyyy,DOJ) between 2005 and 2017) and Status =0
group by DeptID
Union 
Select Count(EmpID) AS T1 From EmployeeDetails WHERE Status =0`

Answer 1

我认为您的查询存在一些语法错误。无论如何，如果总计必须具有相同的部分总数（年度范围），你可以使用：（我简化了创建date_year列的表，但是你可以替换你的条件）

SELECT DeptID, COUNT(EmpID) AS TotalHeadCount  
FROM EmployeeDetails 
WHERE DATE_YEAR between 2005 and 2017 
    AND STATUS =0 
GROUP BY DEPTID
WITH ROLLUP

示例数据：

CREATE TABLE EmployeeDetails (EmpID INT, DEPTID INT, DATE_YEAR INT, STATUS INT);
INSERT INTO EmployeeDetails VALUES (1,1,2004,0);
INSERT INTO EmployeeDetails VALUES (2,1,2005,0);
INSERT INTO EmployeeDetails VALUES (3,1,2005,0);
INSERT INTO EmployeeDetails VALUES (4,1,2006,0);
INSERT INTO EmployeeDetails VALUES (5,1,2007,0);
INSERT INTO EmployeeDetails VALUES (5,1,2008,0);
INSERT INTO EmployeeDetails VALUES (6,1,2009,0);

输出：

DeptID      TotalHeadCount
----------- --------------
1           6
NULL        6

Answer 2

这是怎么回事，

SELECT DeptID, COUNT(EmpID) AS TotalHeadCount  FROM EmployeeDetails          
WHERE (datepart(yyyy,DOJ) between 2005 and 2017) and Status =0
group by DeptID WITH CUBE

如何在不使用Union的情况下获取页脚部分的人数总和

2 个答案: