我有一个可以任意长度的数组。并需要将其分成几个部分。第一部分的长度为14,长度为16之后
var size1 = 14;
var size2 = 16;
var a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21,
22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40];
var arrays = [];
if (a.length > 14){
for (i = 0; i < 14; i++) {
arrays.push(a.splice(0, size1));
}
for (i = 14 ; i < a.length; i++){
arrays.push(a.splice(0, size2));
}
} else {
arrays.push(a.splice(0, size1));
}
console.log(arrays);
然而,基于我正在做的事情,我的阵列只能在14处分裂。你能就我如何做到这一点提出建议吗?
谢谢
答案 0 :(得分:1)
使用Array.prototype.slice()
函数的解决方案:
var a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21,
22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40],
size1 = 14,
size2 = 16,
arrays = [];
[0, size1, size2].forEach(function (v, i, arr) {
arrays.push((arr[i+1])? a.slice(v, v + arr[i+1]) : a.slice(arr[i-1] + v));
});
console.log(arrays);
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答案 1 :(得分:1)
您可以使用数组作为块长度,其余部分使用零,并通过保留前面长度的长度来映射块。
适用于任意数量的块。
var chunks = [14, 16, 0],
array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40],
result = chunks.map((last => a => array.slice(last, a ? (last += a) : undefined))(0));
console.log(result);
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.as-console-wrapper { max-height: 100% !important; top: 0; }
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答案 2 :(得分:0)
你可以尝试使用所有动态数组大小,它会得到你想要的输出。 希望您正在寻找这个解决方案。
var size1 = 14;
var size2 = 16;
var flag=0;
var a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21,
22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40];
var arrays = [];
var t=a.length/14;
while(a.length>0){
if (flag==0 && a.length > 14){
arrays.push(a.splice(0, size1));
flag=1;
} else if(a.length>=16){
arrays.push(a.splice(0, size2));
}
else{
arrays.push(a.splice(0, a.length));
}
}
console.log(arrays)