Question

我有一个数组

array
(
[0] => bruce
)

array
(
[1] => arju
)

我想将上面的数组拆分成多个数组例如：显示在下面

SELECT
    t.id
,   t.expired
,   t.succ
,   t.cradit_end_date
,   t.user_id
,   u.family
,   t.coupon_code
,   u.username
,   d.title
,   s.title as sub_title
,   t.coupon_parent
,   t.coupon_id
,   t.coupon_property_id
FROM tractions t
LEFT OUTER JOIN traction_details d ON t.id = d.tr_id
LEFT OUTER JOIN traction_details_sub s ON t.id = s.tr_id
JOIN users u ON t.user_id = u.id
WHERE t.app='mobile' AND t.succ = 1 AND t.user_id=$user_id

Answer 1

这应该有效，

<?php
$newarr1 = $_SESSION['arrt1'];
echo '<pre>';
print_r($newarr1);
echo '<pre>';
$newarray2 = array();
$i = 0;

while ($i < sizeof($newarr1))
{
    $newarray2[] = array(
        "person_id" => $i + 1,
        "person_name" => $newarr1[$i]
    );
    $i++;
}

?>

编辑：

<?php
$newarr1 = $_SESSION['arrt1'];
echo '<pre>';
print_r($newarr1);
echo '<pre>';
$newarray2 = array();
$i = 0;

while ($i < sizeof($newarr1))
{
    $newarray2[] = array(
        $i => $newarr1[$i]
    );
    $i++;
}

?>

Answer 2

介意我问你为什么要这样的东西？

<?php

  $names = Array(
    'bruce',
    'arju',
    'newu',
    'jack',
    'john',
    'kyle',
    'sam',
    'tim'
  );

  for($i = 0; $i < count($names); $i++){
    $name[] = array($i => $names[$i]);
  }

  foreach($name as $key => $val){
    echo $key, ':<pre>';
    print_r($val);
    echo '</pre>'
  }

  // or you could use array_chunk
  // http://php.net/manual/en/function.array-chunk.php
  print_r(array_chunk($names, 1));

?>

Answer 3

PHP array_chunk可能有所帮助要打破单个数组中的数组，可以使用

$a = array_chunk($input_array, 1); 
echo '<pre>';
print_r($a);
echo '</pre>';

这会给你的结果.....

将数组拆分为单个数组

3 个答案: