我有下面的数据结构,我试图返回顶级键(lo,eth0或eth1),如果在任何地方递归和任意深入它的值是一个给定的字符串。然后在找到第一个字符串实例后终止搜索。
Find key/value pairs deep inside a hash containing an arbitrary number of nested hashes and arrays 这有点类似于我尝试做的事情,但我还没能把它映射到我自己的问题
h.find{ |k,v| break k if v.include? "number" }
=> "eth0"
h.find{ |k,v| break k if v.include? "10.0.128.26" }
=> nil
#Should return eth0
我想知道如何通常使用这样的嵌套数据结构,但我能够在特定的子哈希中专门搜索,在我的情况下使用地址。
h = \
{"lo"=>
{"mtu"=>"65536",
"flags"=>["LOOPBACK", "UP", "LOWER_UP"],
"encapsulation"=>"Loopback",
"addresses"=>
{"127.0.0.1"=>
{"family"=>"inet",
"prefixlen"=>"8",
"netmask"=>"255.0.0.0",
"scope"=>"Node"}},
"state"=>"unknown"},
"eth0"=>
{"type"=>"eth",
"number"=>"0",
"mtu"=>"1500",
"flags"=>["BROADCAST", "MULTICAST", "UP", "LOWER_UP"],
"encapsulation"=>"Ethernet",
"addresses"=>
{"00:0C:29:1A:64:6A"=>{"family"=>"lladdr"},
"10.0.128.26"=>
{"family"=>"inet",
"prefixlen"=>"24",
"netmask"=>"255.255.255.0",
"broadcast"=>"10.0.128.255",
"scope"=>"Global"}},
"state"=>"up",
"arp"=>
{"10.0.128.31"=>"00:0c:29:04:12:9a",
"10.0.128.100"=>"00:0c:29:5b:b4:46",
"10.0.128.30"=>"00:0c:29:05:a4:c7",
"10.0.128.18"=>"00:0c:29:6a:3f:75",
"10.0.128.3"=>"0c:c4:7a:c0:31:d1",
"10.0.128.43"=>"00:0c:29:01:eb:6b",
"10.0.128.44"=>"00:09:0f:09:00:03",
"10.0.128.14"=>"00:0c:29:d2:15:80",
"10.0.128.22"=>"00:0c:29:18:99:30"},
"routes"=>
[{"destination"=>"10.0.128.0/24",
"family"=>"inet",
"scope"=>"link",
"proto"=>"kernel",
"src"=>"10.0.128.26"}],
"link_speed"=>10000,
"duplex"=>"Full",
"port"=>"Twisted Pair",
"transceiver"=>"internal",
"auto_negotiation"=>"off",
"mdi_x"=>"Unknown",
"ring_params"=>
{"max_rx"=>4096,
"max_rx_mini"=>0,
"max_rx_jumbo"=>2048,
"max_tx"=>4096,
"current_rx"=>256,
"current_rx_mini"=>0,
"current_rx_jumbo"=>128,
"current_tx"=>512}},
"eth1"=>
{"type"=>"eth",
"number"=>"1",
"mtu"=>"1500",
"flags"=>["BROADCAST", "MULTICAST", "UP", "LOWER_UP"],
"encapsulation"=>"Ethernet",
"addresses"=>
{"00:0C:29:1A:64:74"=>{"family"=>"lladdr"},
"11.11.11.1"=>
{"family"=>"inet",
"prefixlen"=>"24",
"netmask"=>"255.255.255.0",
"broadcast"=>"11.11.11.1",
"scope"=>"Global"}},
"state"=>"up",
"routes"=>
[{"destination"=>"default", "family"=>"inet", "via"=>"11.11.11.1"},
{"destination"=>"11.11.11.1/24",
"family"=>"inet",
"scope"=>"link",
"proto"=>"kernel",
"src"=>"11.11.11.1"}],
"link_speed"=>10000,
"duplex"=>"Full",
"port"=>"Twisted Pair",
"transceiver"=>"internal",
"auto_negotiation"=>"off",
"mdi_x"=>"Unknown",
"ring_params"=>
{"max_rx"=>4096,
"max_rx_mini"=>0,
"max_rx_jumbo"=>2048,
"max_tx"=>4096,
"current_rx"=>256,
"current_rx_mini"=>0,
"current_rx_jumbo"=>128,
"current_tx"=>512}}}
答案 0 :(得分:3)
由于您对顶级密钥感兴趣,您可以执行以下操作:
hash.find{ |k,v| break k if v.to_s.include? "10.0.128.26" }
#=> eth0
通过使用v.to_s
,我们能够搜索哈希的字符串表示,并且还能够避免递归。
答案 1 :(得分:1)
如果您想返回顶级父密钥,可以使用顶级哈希密钥的mentioned answer和find
以简单的方式执行此操作
#return true if find or nil
def deep_key?(obj, key)
if obj.respond_to?(:key?) && obj.key?(key)
true
elsif obj.respond_to?(:each)
r = nil
obj.find{ |*a| r = deep_key?(a.last, key) }
r
end
end
key = '00:0C:29:1A:64:74'
#now you check if the provided key is a top level key or run search
h.key?(key) ? key : h.find { |k, v| deep_key?(v, key) }.first
deep_key?
它是来自上述答案的一点修改后的搜索功能,如果找到一个键则返回true
(如果找不到,则返回nil
)。你可以在Hash#find
block - top-level key中使用这个函数,如果找到了它的结果(添加first
只返回一个键)。