我有两个矩形(条纹)我想点击条纹用鼠标上下移动它然后使用K_UP和K_DOWN键移动相同的条纹。使用我编写的代码,我可以用鼠标移动条纹,但键同时移动两个条纹而不是单独移动。我只有一周的程序员,请帮忙!
import pygame
import pygame.gfxdraw
pygame.init()
width, height = 800, 600
gameWindow = pygame.display.set_mode((width, height))
pygame.display.set_caption("Koordynacja LoL")
clock = pygame.time.Clock()
# Colors
white = (255, 255, 255)
black = (0, 0, 0)
red = (255, 0, 0)
blue = (0, 0, 255)
green = (0, 102, 0)
yellow = (255, 204, 0)
grid_color = (224, 224, 224)
k = 5
class Stripe():
def __init__(self, color, size, pos_x, pos_y):
self.size = size
self.image = pygame.Surface(size)
self.image.fill(color)
self.rect = self.image.get_rect()
self.pos_x = pos_x
self.pos_y = pos_y
self.rect.x = pos_x
self.rect.y = pos_y
self.speed = 5
def move(self, xdir, ydir):
self.rect.x += xdir * self.speed
self.rect.y += ydir * self.speed
P1_len = 250
stripe1 = Stripe(green, (15, P1_len), 100, 200)
stripe_1a = Stripe(0, (15, 1000), 100, 0)
stripe_1aa = gameWindow.blit(stripe_1a.image, stripe_1a.rect)
P2_len = 110
stripe2 = Stripe(red, (15, P2_len), 200, 100)
stripe_2a = Stripe(0, (15, 1000), 200, 0)
stripe_2aa = gameWindow.blit(stripe_2a.image, stripe_2a.rect)
zielone2 = gameWindow.blit(stripe2.image, stripe2.rect)
pygame.display.update()
FPS = 15
Running = True
stripe_move = None
while Running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
Running = False
(mouseX, mouseY) = pygame.mouse.get_pos()
(p1, p2, p3) = pygame.mouse.get_pressed()
if stripe_1aa.collidepoint(mouseX, mouseY) and p1 == 1:
stripe1 = Stripe(green, (15, 250), 100, mouseY-P1_len)
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_DOWN:
stripe1.move(0, 1)
print("lol")
if event.key == pygame.K_UP:
stripe1.move(0, -1)
elif stripe_2aa.collidepoint(mouseX, mouseY) and p1 == 1:
stripe2 = Stripe(red, (15, 110), 200, mouseY - P2_len)
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_DOWN:
stripe2.move(0, 1)
if event.key == pygame.K_UP:
stripe2.move(0, -1)
print("wut?")
elif event.type == pygame.MOUSEBUTTONUP:
stripe_move = None
gameWindow.fill((255, 255, 255))
# Draw stuff here
""" Greedy Grid """
for i in range(width):
grid_x = k * i
grid_y = k * i
pygame.draw.line(gameWindow, grid_color, (grid_x, 0), (grid_x, height), 1)
pygame.draw.line(gameWindow, grid_color, (0, grid_y), (width, grid_y), 1)
pygame.draw.line(gameWindow, black, (2 * k, height - 2 * k), (width - 2 * k, height - 2 * k), 3)
pygame.draw.line(gameWindow, black, (2 * k, height - 2 * k), (2 * k, 2 * k), 3)
pygame.draw.aaline(gameWindow, black, (2 * k, 2 * k), (width - 2 * k, 2 * k), 3)
pygame.draw.aaline(gameWindow, blue, (200, 115), (500, 70), True)
gameWindow.blit(stripe1.image, stripe1.rect)
gameWindow.blit(stripe2.image, stripe2.rect)
# End draw stuff here
pygame.display.update()
clock.tick(FPS)
pygame.quit()
quit()
enter code here
答案 0 :(得分:1)
我将按如下方式构造代码:如果单击鼠标并且event.pos
与条带冲突,请将该条带分配给变量(selected_stripe
),并将其设置为{{1如果用户点击其他地方。只要鼠标按钮停止,也会将None
变量设置为scrolling
。在事件循环之外,您可以将所选条带的y位置设置为鼠标位置。对于向上和向下键,您只需使用所选条带的True
方法。
move