Question

我的代码......

sentence = "hello world helloworld"

dictionary = {"hello": "1", "world": "2", "helloworld": "3"}

for key in dictionary:
    sentence = sentence.replace(key, dictionary[key])

print(sentence)

我想要它做什么...

1 2 3

实际上做了什么......

1 2 12

Answer 1

试试这个：

sentence = "hello world helloworld"
sentence = sentence.split()

dictionary = {"hello": "1", "world": "2", "helloworld": "3"}

print ' '.join(map(lambda x: dictionary.get(x) or x , sentence))

Answer 2

如果你的句子可以包含不在你的词典中的单词，应该不加改变地返回，请尝试这种方法：

sentence = "hello world helloworld missing words"
sentence = sentence.split()

dictionary = {"hello": "1", "world": "2", "helloworld": "3"}

for i, word in enumerate(sentence):
    sentence[i] = dictionary[word] if word in dictionary else word

print(" ".join(sentence))

Answer 3

替换的顺序很重要。在你的情况下：

当hello被替换时：“1 world 1world”
首次替换world时：“1 2 12”

为了避免它按照长度的顺序迭代键。从最长到短。

for key in dictionary.keys().sort( lambda aa,bb: len(aa) - len(bb) ):
    sentence = sentence.replace(key, dictionary[key])

如何用字典中的值替换字符串？蟒蛇

3 个答案: