Question

我是MySQL的新手，我试图在我的Java代码中实现它。我想要做的是根据记录是否已经存在来调用方法，更新/插入数据库表。

现在，我已经浏览了StackOverflow和Goggle，从我发现的内容来看，我需要确保在命令中删除值之间的空格，并且每个值都带有前缀并以＆＃39为后缀;。然而，这似乎并没有削减它。我仍然收到错误You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

我不知道为什么这是因为我遵循我在教程网站和论坛上看到的语法，但它似乎仍然是不正确的。我知道问题不是我的主人，因为我可以轻松连接并查询。这是我的代码：

                if (!syncedPlayers.contains(player)) {
                worked = database.command("INSERT INTO " +
                        TABLE_NAME + " " + UUID_FIELD + "," + CAPTURE_FIELD + "," + FFA_FIELD + "," + GEANT_FIELD + "," + QUIZZ_FIELD + "," + SURVIE_FIELD +
                        " VALUES ('" + player.toString() + "','" +
                        getScores(CAPTURE_FIELD, player, field, amount) + "','" +
                        getScores(FFA_FIELD, player, field, amount) + "','" +
                        getScores(GEANT_FIELD, player, field, amount) + "','" +
                        getScores(QUIZZ_FIELD, player, field, amount) + "','" +
                        getScores(SURVIE_FIELD, player, field, amount) + "'");
            } else {
                worked = database.command(
                        "UPDATE " + TABLE_NAME +
                                " SET " + field + " = '" + getScores(field, player, field, amount) +
                                "' WHERE " + UUID_FIELD + " = '" + player.toString() + "'");
            }

每个getScores(<FIELD>, <UUID>, <FIELD2>, <INTEGER>始终返回一个整数值。所以你可以把它们想象成只有35或123或0等。我也使用一个名为SpigotLib的SQL包装器来简化java SQL。

我是SQL的完全新手，所以如果这看起来像一个简单的问题，请不要被冒犯。

Answer 1

您从未关闭VALUES (

你的最后一行应该是

getScores(SURVIE_FIELD, player, field, amount) + "')");

Java MySQL语法错误不会消失

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