Question

我已经在Javascript中创建了一个类，但我想在我的for (var key in family_background) { family_background[key] = null; }中创建一个Ajax请求，并且返回到我的对象属性，但它不起作用。我哪里错了？

constructor

Answer 1

当您使用jQuery的AJAX函数时，回调中this的值是对请求对象的引用。如果要从父作用域访问this的值，请使用.bind：

    jQuery.ajax({
       url: '../php/consulta.php' + location.search,
       type: "GET",
       dataType: 'json',
       success: function(pergunta, desafio){
           this.perguntas = pergunta.pergunta;
           this.respostas = pergunta.resposta;
           this.desafios = desafio.descricao;

         }.bind(this)
       });

如果您需要支持不允许.bind的浏览器，请使用额外的变量：

class pergunta {
      constructor(perguntas = [], respostas = [], desafios = [], valor = 100, posicao = 0){
        var _this = this;
        this.perguntas = perguntas;
        this.respostas = respostas;
        this.desafios = desafios;
        this.posicao = posicao;
        this.valor = valor;
        jQuery.ajax({
           url: '../php/consulta.php' + location.search,
           type: "GET",
           dataType: 'json',
           success: function(pergunta, desafio){
               _this.perguntas = pergunta.pergunta;
               _this.respostas = pergunta.resposta;
               _this.desafios = desafio.descricao;

             }
           });

}

在Javascript / Jquery中有一次需要的东西

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