Question

我通过POST从表单中获取了大量数据。例如，以下是一些数据：

EVENT_DATE：

Array (
    [0] => 2017-04-02
    [1] => 2017-04-02
    [2] => 2017-04-03 )

equipment_name：

Array
(
    [0] => Array
        (
            [0] => Mic
            [1] => Sound System
            [2] => Wireless Mic
            [3] => Two Point Stage Wash
        )

    [1] => Array
        (
            [0] => Sound System
        )

    [2] => Array
        (
            [0] => Projection Package
            [1] => Gobo
            [2] => Audio Engineer
        )
)

为了保存这些数据，我正在做两个foreach循环：

foreach ($_POST['event_date'] as $key => $date) {
    echo "event number [".$key."]<br>";
    //insert into table value $_POST['event_date'][$key]

    foreach ($_POST['equipment_name'] as $ekey => $value) {
        echo "equipment number [".$key."][".$ekey."]<br>";
        //insert into table value $_POST['equipment_name'][$key][$ekey];
    }
}

不幸的是我的结果如下：

event number [0]
   equipment number [0][0]
   equipment number [0][1]
   equipment number [0][2]
event number [1]
   equipment number [1][0]
   equipment number [1][1]
   equipment number [1][2]
event number [2]
   equipment number [2][0]
   equipment number [2][1]
   equipment number [2][2]

您可以注意到，嵌套密钥（$ ekey）等于第一个密钥，不显示超过该数字的项目（例如：设备编号[0] [3]），如果设备数量低于设备数量则不保存任何内容该编号（例如：设备编号[1] [1]和[1] [2]）。

为什么嵌套循环有这种行为？我怎么能解决这个问题？

Answer 1

如果我理解你的问题，我认为你想从$_POST['equipment_name']访问一个特定的嵌套数组，但你总是访问外部数组。这是一个简单的修复，将您的第二个foreach更改为：

foreach ($_POST['equipment_name'][$key] as $ekey => $value) {
                                 ^^^^^^

PHP嵌套的foreach只取第一个键

1 个答案: