我一直试图解决这个问题两天,而且正在撞砖墙。我有一个skyscanner数组,它有飞行路线,我有航班
Leg - being Itineraries -> OutboundLegId -
以及显示航班号的腿 - 是
Legs -> FlightNumbers -> FlightNumber.
我想要实现的是显示行程,然后将航班号加入到该行程中。但无论我尝试什么,我都无法让它发挥作用。我已经在这里阅读了关于Keys的所有内容,并尝试了很多示例,但我什么都没有。有人能指出我正确的方向吗?
下面的示例数组
[Itineraries] => Array
(
[0] => Array
(
[OutboundLegId] => 13542-1610140610-29-0-13445-1610141240
[InboundLegId] => 13445-1610211340-29-0-13542-1610211640
[PricingOptions] => Array
(
[0] => Array
(
[Agents] => Array
(
[0] => 2174187
)
[QuoteAgeInMinutes] => 31
[Price] => 200.98
[DeeplinkUrl] => http://partners.api.skyscanner.net/apiservices/deeplink/v2?_cje=5JlLCgyPUKY0hT8T0Ybh6dL0Xf0htAiHTFX7RU79eeI3XvrsxvEqP1QUJAoHiHRd&url=http%3a%2f%2fwww.apideeplink.com%2ftransport_deeplink%2f4.0%2fUK%2fen-gb%2fGBP%2fcook%2f2%2f13542.13445.2016-10-14%2c13445.13542.2016-10-21%2fair%2fairli%2fflights%3fitinerary%3dflight%7c-32294%7c1152%7c13542%7c2016-10-14T06%3a10%7c13445%7c2016-10-14T12%3a40%2cflight%7c-32294%7c1153%7c13445%7c2016-10-21T13%3a40%7c13542%7c2016-10-21T16%3a40%26carriers%3d-32294%26passengers%3d1%2c0%2c0%26channel%3ddataapi%26cabin_class%3deconomy%26facilitated%3dfalse%26ticket_price%3d200.98%26is_npt%3dfalse%26is_multipart%3dfalse%26client_id%3dskyscanner_b2b%26request_id%3d3bc96bda-fd7c-403a-b841-2ccc3c26071d%26commercial_filters%3dfalse%26q_datetime_utc%3d2016-09-29T08%3a18%3a27
)
[Legs] => Array
(
[0] => Array
(
[Id] => 13542-1610140610-29-0-13445-1610141240
[SegmentIds] => Array
(
[0] => 1
)
[OriginStation] => 13542
[DestinationStation] => 13445
[Departure] => 2016-10-14T06:10:00
[Arrival] => 2016-10-14T12:40:00
[Duration] => 270
[JourneyMode] => Flight
[Stops] => Array
(
)
[Carriers] => Array
(
[0] => 105
)
[OperatingCarriers] => Array
(
[0] => 105
)
[Directionality] => Outbound
[FlightNumbers] => Array
(
[0] => Array
(
[FlightNumber] => 1152
[CarrierId] => 105
)
)
)
答案 0 :(得分:0)
将其用作草稿。没有反馈就无法执行功能。 放置正确的数组而不是{YOUR-ARRAY-WITH-LEGS}和{YOUR-ARRAY-WITH-ITINERARIES}
$sortedLegs = array_column('Id', {YOUR-ARRAY-WITH-LEGS});
$joinedArray = array_map(function($itinerary) use($sortedLegs){
if(array_key_exists($itinerary['OutboundLegId'],$sortedLegs)) {
$itinerary['legs'] = $sortedLegs[$itinerary['OutboundLegId']];
}
return $itinerary;
},{YOUR-ARRAY-WITH-ITINERARIES});
答案 1 :(得分:0)
假设这是一个大数组并且它被称为$data
,你可以嵌套几个foreach循环。
我使用foreach循环,因为我认为有些情况下这个数据结构比你显示的更复杂
foreach ( $data['Itineraries'] as $itin ) {
foreach ( $data['Legs'] as $legs) {
if ($legs['Id'] == $itin['OutboundLegId']) {
// we matched the itinerary with a leg
echo $legs['OutboundLegId'] . ' ' . $legs['FlightNumbers'][0]['FlightNumber'];
}
}
}