Question

真的很难找到答案。

我创建了一个游戏，它会询问有多少玩家，用户可以输入的最大玩家数量是3（1,2或3）。这是创建for循环还是我可以在扫描仪功能中输入参数？

以下代码：

System.out.println(" How many players are there? ");

int numberOfPlayers = scan.nextInt();

Player[] players = new Player[numberOfPlayers]; //this is where the players scores are stored
int currentPlayer = 0;  //because arrays start at 0: +1 is added

for (int i = 0; i < numberOfPlayers; i++) {

    System.out.println("What is player " + (i + 1) + " called?");
    String playerName = scan.next();
    players[i] = new Player(playerName);

Answer 1

您可以使用Scanner的nextLine()来读取换行符而不是next()，如下所示：

    System.out.println(" How many players are there? ");
    int numberOfPlayers = Integer.parseInt(scan.nextLine());
    Player[] players = new Player[numberOfPlayers];
    for (int i = 0; i < numberOfPlayers; i++) {
        System.out.println("What is player " + (i + 1) + " called?");
        String playerName = scan.nextLine();
        players[i] = new Player(playerName);
    }

Answer 2

我建议将Integer.parseInt(scan.nextLine())与循环一起使用，例如：

int numberOfPlayers = 0;
boolean correct = false;
do {
    try {
        System.out.println(" How many players are there? ");
        numberOfPlayers = Integer.parseInt(scan.nextLine());
        if (numberOfPlayers >= 1 && numberOfPlayers <= 3) {
            correct = true;
        }
    } catch (NumberFormatException e) {
    }
} while (!correct);

因此，如果用户输入错误的号码或号码> 3或< 1，则会要求用户再次输入号码，直到用户输入正确的号码1,2,3

Java扫描程序 - 允许一定数量的整数

2 个答案: