PHP:将多个jsons的数据组合到数组中

时间:2017-04-29 12:06:50

标签: php arrays array-merge array-push

我有以下数据(我还有更多)。

$item1 = '{"views":{"Greece":{"total":10},"Cyprus":{"total":23},"Bulgaria":{"total":1},"United States":{"total":53},"United Kingdom":{"total":11},"Spain":{"total":2},"India":{"total":1},"":{"total":1},"Finland":{"total":2},"France":{"total":2},"Sweden":{"total":1},"Germany":{"total":5},"Ireland":{"total":1},"Austria":{"total":2},"Switzerland":{"total":2},"Poland":{"total":1},"Mexico":{"total":1}},"clicks":{"Greece":{"total":310},"Bulgaria":{"total":1},"United Kingdom":{"total":4},"United States":{"total":3},"Cyprus":{"total":15},"Finland":{"total":1},"Germany":{"total":1},"Ireland":{"total":1},"Spain":{"total":1},"Poland":{"total":1}},"leads":{"Greece":{"total":9}}}';

$item2 = '{"views":{"Greece":{"total":15},"Cyprus":{"total":1},"Bulgaria":{"total":1},"United States":{"total":53},"United Kingdom":{"total":11},"Spain":{"total":2},"India":{"total":1},"":{"total":1},"Finland":{"total":2},"France":{"total":2},"Sweden":{"total":1},"Germany":{"total":5},"Ireland":{"total":1},"Austria":{"total":2},"Switzerland":{"total":2},"Poland":{"total":1},"Mexico":{"total":1}},"clicks":{"Greece":{"total":310},"Bulgaria":{"total":1},"United Kingdom":{"total":4},"United States":{"total":3},"Cyprus":{"total":15},"Finland":{"total":1},"Germany":{"total":1},"Ireland":{"total":1},"Spain":{"total":1},"Poland":{"total":1}},"leads":{"Greece":{"total":9}}}';

最初我创建了一个循环,所以我可以遍历那些(我在示例中只展示了2个)

for ( $x = 1; $x <= 2; $x++ ) {

$theitem = 'item' . $x;
$countries = json_decode( $$theitem, true );


$keys = array_keys( $countries[ 'views' ] );
$arraySize = count( $countries[ 'views' ] );


for ( $i = 0; $i < $arraySize; $i++ ) {

    if ( $keys[ $i ] == '' ) {
        echo "Empty: ";
    } else {
        echo $keys[ $i ] . ": ";
    }


    echo $countries[ 'views' ][ $keys[ $i ] ][ 'total' ];
    echo "<br>";

    // 

}
}

我需要在循环中执行以下操作:

1)创建一个新数组并添加Country + Total Number

2)如果Country中已存在Country,则只需将Total Number添加到现有项目中

3)最后,我将有一个数组,其中只包含每个不同国家/地区的总视图。

我需要一些帮助,有人可以提供帮助:)

1 个答案:

答案 0 :(得分:0)

这里我们使用简单的foreach循环和function来添加结果数组中的值。

Try this code snippet here

<?php

ini_set('display_errors', 1);
$item1 = '{"views":{"Greece":{"total":10},"Cyprus":{"total":23},"Bulgaria":{"total":1},"United States":{"total":53},"United Kingdom":{"total":11},"Spain":{"total":2},"India":{"total":1},"":{"total":1},"Finland":{"total":2},"France":{"total":2},"Sweden":{"total":1},"Germany":{"total":5},"Ireland":{"total":1},"Austria":{"total":2},"Switzerland":{"total":2},"Poland":{"total":1},"Mexico":{"total":1}},"clicks":{"Greece":{"total":310},"Bulgaria":{"total":1},"United Kingdom":{"total":4},"United States":{"total":3},"Cyprus":{"total":15},"Finland":{"total":1},"Germany":{"total":1},"Ireland":{"total":1},"Spain":{"total":1},"Poland":{"total":1}},"leads":{"Greece":{"total":9}}}';

$item2 = '{"views":{"Greece":{"total":15},"Cyprus":{"total":1},"Bulgaria":{"total":1},"United States":{"total":53},"United Kingdom":{"total":11},"Spain":{"total":2},"India":{"total":1},"":{"total":1},"Finland":{"total":2},"France":{"total":2},"Sweden":{"total":1},"Germany":{"total":5},"Ireland":{"total":1},"Austria":{"total":2},"Switzerland":{"total":2},"Poland":{"total":1},"Mexico":{"total":1}},"clicks":{"Greece":{"total":310},"Bulgaria":{"total":1},"United Kingdom":{"total":4},"United States":{"total":3},"Cyprus":{"total":15},"Finland":{"total":1},"Germany":{"total":1},"Ireland":{"total":1},"Spain":{"total":1},"Poland":{"total":1}},"leads":{"Greece":{"total":9}}}';


$result=array();
getCount(json_decode($item1,true));
getCount(json_decode($item2,true));
print_r($result);
function getCount($array1)
{
    global $result;
    foreach($array1 as $key => $value)
    {
        foreach($value as $country => $data)
        {
            if(!isset($result[$country]))
            {
                $result[$country]=$data["total"];
            }
            else
            {
                $result[$country]+=$data["total"];
            }
        }
    }
}