Question

我想要组合2个json对象。我尝试使用concat和merge函数，但结果不是我想要的。任何帮助将不胜感激。

var jason1 = 
{
  "book1": {
    "price": 10,
    "weight": 30
  },
  "book2": {
    "price": 40,
    "weight": 60
  }
};

这是另一个对象

var jason2 =
{
  "book3": {
    "price": 70,
    "weight": 100
  },
  "book4": {
    "price": 110,
    "weight": 130
  }
};

这就是我想要的：

var jasons =
{
  "book1": {
    "price": 10,
    "weight": 30
  },
  "book2": {
    "price": 40,
    "weight": 60
  }
  "book3": {
    "price": 70,
    "weight": 100
  },
  "book4": {
    "price": 110,
    "weight": 130
  }
};

Answer 1

从Prototype.js框架中查看Object.extend方法的来源：

https://github.com/sstephenson/prototype/blob/master/src/prototype/lang/object.js#L88

function extend(destination, source) {
  for (var property in source) {
    destination[property] = source[property];
  }
}

然后使用......

extend(jason1, jason2);

对象jason1现在包含您想要的内容。

Answer 2

你需要手动迭代它们：

var both = [json1, json2],
    jasons = {};


for (var i=0; i < both.length; i++) {
  for (var k in both[i]) {
    if(both[i].hasOwnProperty(k)) {
       jasons[k] = both[i][k];
    }
  }
}

继承人工作fiddle。您可能想要考虑如果存在重复键会发生什么 - 例如，如果两个json对象中都存在book3，那该怎么办？使用我提供的代码，第二个中的值总是获胜。

Answer 3

这是一种方式，虽然我确信有更优雅的解决方案。

var jason1 = {
    "book1": {
        "price": 10,
        "weight": 30
    },
    "book2": {
        "price": 40,
        "weight": 60
    }
};
var jason2 = {
    "book3": {
        "price": 70,
        "weight": 100
    },
    "book4": {
        "price": 110,
        "weight": 130
    }
};
var jasons = {};
var key;
for (key in jason1) {
    if (jason1.hasOwnProperty(key) && !(jasons.hasOwnProperty(key))) {
        jasons[key] = jason1[key];
    }
}
for (key in jason2) {
    if (jason2.hasOwnProperty(key) && !(jasons.hasOwnProperty(key))) {
        jasons[key] = jason2[key];
    }
}
console.log(jasons);

组合2个json对象

3 个答案: