Question

这是我的json：

{  
   "all_counts_reports":{  
      "26":{  
         "name":"kumar",
         "date":"2017-04-27",
         "trips_per_day":"2",
         "cash_trips":"0",
         "credit_trips":"1",
         "compliment_trips":"1"
      },
      "28":{  
         "name":"kumar",
         "date":"2017-04-29",
         "trips_per_day":"1",
         "cash_trips":"1",
         "credit_trips":"0",
         "compliment_trips":"0"
      }
   }
}

我想使用PHP删除第二级密钥（例如"26:"和"28":）。

换句话说，我想用零索引数字键替换双引号码。

如何让它看起来像这样：

{"all_counts_reports":
    [
        {"name":"kumar",
         "date":"2017-04-27",
         "trips_per_day":"2",
         "cash_trips":"0",
         "credit_trips":"1",
         "compliment_trips":"1"
        },
        {"name":"kumar",
         "date":"2017-04-29",
         "trips_per_day":"1",
         "cash_trips":"1",
         "credit_trips":"0",
         "compliment_trips":"0"
        }
    ]
}

Answer 1

这是demo。

代码：

// declare $json
$array=json_decode($json,true);  // decode as array
// overwrite subarray with zero-indexed keys while preserving subarray values
$array['all_counts_reports']=array_values($array['all_counts_reports']);
var_export(json_encode($array));  // return to json

输入：

$json='{  
   "all_counts_reports":{  
      "26":{  
         "name":"kumar",
         "date":"2017-04-27",
         "trips_per_day":"2",
         "cash_trips":"0",
         "credit_trips":"1",
         "compliment_trips":"1"
      },
      "28":{  
         "name":"kumar",
         "date":"2017-04-29",
         "trips_per_day":"1",
         "cash_trips":"1",
         "credit_trips":"0",
         "compliment_trips":"0"
      }
   }
}';

输出：

'{"all_counts_reports":
    [
        {"name":"kumar",
         "date":"2017-04-27",
         "trips_per_day":"2",
         "cash_trips":"0",
         "credit_trips":"1",
         "compliment_trips":"1"
        },
        {"name":"kumar",
         "date":"2017-04-29",
         "trips_per_day":"1",
         "cash_trips":"1",
         "credit_trips":"0",
         "compliment_trips":"0"
        }
    ]
}'

在您的javascript中，使用JSON.parse()去除包装单引号：

var str='{"all_counts_reports":[{"name":"kumar","date":"2017-04-27","trips_per_day":"2","cash_trips":"0","credit_trips":"1","compliment_trips":"1"},{"name":"kumar","date":"2017-04-29","trips_per_day":"1","cash_trips":"1","credit_trips":"0","compliment_trips":"0"}]}';
var json=JSON.parse(str);
console.log(json);

因为我们正在运行假设，如果你想删除all_counts_reports键，你可以使用这个单行：

代码：

$new_json=json_encode(array_values(current(json_decode($json,true))));

输出：

'[{"name":"kumar","date":"2017-04-27","trips_per_day":"2","cash_trips":"0","credit_trips":"1","compliment_trips":"1"},{"name":"kumar","date":"2017-04-29","trips_per_day":"1","cash_trips":"1","credit_trips":"0","compliment_trips":"0"}]'

Answer 2

$array = json_decode($your_json_string,true);
print_r($array);
$result = array();
foreach($array['all_counts_reports'] as $rep){
    $result['all_counts_reports'][] = array(
        "name"=>$rep['name'],
        "date"=>$rep['date'],
        "trips_per_day"=>$rep['trips_per_day'],
        "cash_trips"=>$rep['cash_trips'],
        "credit_trips"=>$rep['credit_trips'],
        "compliment_trips"=>$rep['compliment_trips'], 
    );
}

$result_json = json_encode($result);
echo $result_json;

可能有更好的解决方案，但现在就在我的脑海中

目前还不清楚你在寻找什么，如果你只想删除而不想保持原来的json那么你可以这样做。但是，如果您不希望将all_counts_reports视为数组[]，则此示例无效。

简单地传递给android然后上面就可以了。

如何从JSON中删除不需要的嵌套键

2 个答案: