Question

我是Python的新手，在此先感谢您的帮助。

我构建了以下代码（我尝试了以下代码，在词典中使用了词典）。

这个想法是将键（hair.color）保留为values（blonde）。在此示例中：删除Micheal。

代码：

def answers(hair_questions):
    try:
        for i in people:
            if people[i]["hair.color"]==hair_questions:
                print(people[i])
            else:
                del people[i]
            return people[i]
    except:
        print("Doesn´t exist")

answers("brown")

关于人：

people={
 "Anne":
    {
   "gender":"female",
   "skin.color":"white",
  "hair.color":"blonde",
  "hair.shape":"curly"
 }
,
"Michael":
{

  "citizenship":"africa",
  "gender":"male",
  "hair.color":"brown",
  "hair.shape":"curly"


}
,

"Ashley":
    {
  "gender":"female",
  "citizenship":"american",
  "hair.color":"blonde",
  "hair.shape":"curly "
 }

 }

该代码仅检查第一个键：在以下条件下：values(blonde)即(people[i]["hair.color"]!=brown)它仅适用于1个键，然后代码被“卡住”

我当前的输出：

"people"=

 "Michael":
{

  "citizenship":"africa",
  "gender":"male",
  "hair.color":"brown",
  "hair.shape":"curly"


}
,

"Ashley":
    {
  "gender":"female",
  "citizenship":"american",
  "hair.color":"blonde",
  "hair.shape":"curly "
 }

相反，我想要：

"people"=

"Michael":
{

  "citizenship":"africa",
  "gender":"male",
  "hair.color":"brown",
  "hair.shape":"curly"

}

在这种情况下，我想要一个输出（仅）Michael。

Answer 1

迭代循环时不能删除密钥：

people={
    "Anne":
        {
       "gender":"female",
       "skin.color":"white",
      "hair.color":"blonde",
      "hair.shape":"curly"
     },
    "Michael":
    {
      "citizenship":"africa",
      "gender":"male",
      "hair.color":"brown",
      "hair.shape":"curly"
    },
    "Ashley":
        {
          "gender":"female",
          "citizenship":"american",
          "hair.color":"blonde",
          "hair.shape":"curly "
        }
 }

def answers(hair_questions):
    my_dict = {}
    for i in people:
        if people[i]["hair.color"] in hair_questions:
            my_dict[i] = people[i]
    return  my_dict

print(answers("brown"))

OR

def answers(hair_questions):
    my_list = []
    for i in people:
        if people[i]["hair.color"] not in hair_questions:
            my_list.append(i)

    for i in my_list:
        del people[i]

answers("brown")
print(people)

O / P：

{'Michael': {'citizenship': 'africa', 'gender': 'male', 'hair.color': 'brown', 'hair.shape': 'curly'}}

Answer 2

您可以使用列表理解：

brown = {key:value for key,value in people.items() if people[key]["hair.color"] != "blonde"}
print (brown)

等于：

brown= {}
for key,value in people.items():
    if people[key]["hair.color"] != "blonde":
        brown[key] = value
print (brown)

输出：

{'Michael': {'citizenship': 'africa', 'gender': 'male', 'hair.color': 'brown', 'hair.shape': 'curly'}}

从嵌套字典中删除键（Python键）

2 个答案: