iPhone:检测UIAlert / UIActionSheet是否打开

时间:2010-12-06 04:49:37

标签: iphone uialertview uiactionsheet

在我的iOS应用程序中,我有一个计时器启动,当它触发时,我需要能够检测是否有警报(UIAlertView)或操作表(UIActionSheet)打开。

一种方法是修改显示警报/操作表的代码 - 但遗憾的是,在我的情况下,这不是一个选项。

所以,问题是 - 有没有办法知道/检测警报或行动表是否已被打开?

是否在打开时发送了任何通知,或者是否有任何遍历视图层次结构来检测它?

由于

6 个答案:

答案 0 :(得分:17)

他们会在打开时发送提醒,但仅限于delegate - 请检查this question以获得解决该问题的方法。 Techzen建议您在打开警报时将布尔标记设置为YES,并在您关闭警报时将其设置回NO

编辑:

由于您根本无法访问代码,为什么不尝试这段笨重的代码:

-(BOOL) doesAlertViewExist {
  for (UIWindow* window in [UIApplication sharedApplication].windows) {
    NSArray* subviews = window.subviews;
    if ([subviews count] > 0) {

      BOOL alert = [[subviews objectAtIndex:0] isKindOfClass:[UIAlertView class]];
      BOOL action = [[subviews objectAtIndex:0] isKindOfClass:[UIActionSheet class]];

      if (alert || action)
        return YES;
     }
  }
  return NO;
}

答案 1 :(得分:12)

- (BOOL) doesAlertViewExist {
    for (UIWindow* window in [UIApplication sharedApplication].windows) {
        for (UIView* view in window.subviews) {
            BOOL alert = [view isKindOfClass:[UIAlertView class]];
            BOOL action = [view isKindOfClass:[UIActionSheet class]];
            if (alert || action)
                return YES;
        }
    }
    return NO;
}

答案 2 :(得分:2)

您还可以检查视图的窗口属性:

if(actionSheet.window)
    isBeingPresented = YES;

答案 3 :(得分:2)

检测警报似乎相对容易,但行动表让我难过。在iOS 6.1中,我必须更进一步

BOOL IsActionOpen(UIView* aView) {
BOOL    actionOpen = NO;
if (aView) {
    if ([aView isKindOfClass:[UIActionSheet class]]) {
        actionOpen = YES;
    }
    else if (aView.subviews.count > 0) {
        for (UIView* aSubview in aView.subviews) {
            if ( IsActionOpen( aSubview)) {
                actionOpen = YES;
                break;
            }
        }
    }
}
return actionOpen;

}

- (BOOL) isAnActionSheetOpen {
BOOL    actionOpen = NO;
for (UIWindow* w in [UIApplication sharedApplication].windows) {
    actionOpen =  IsActionOpen(w);
    if (actionOpen)
        break;
}
return actionOpen;

}

答案 4 :(得分:1)

thanx的帮助,但自iOS 6以来,代码片不再起作用了。 但是,我修复了此代码的问题。希望这有帮助

for (UIWindow* window in [UIApplication sharedApplication].windows) {
    NSArray* subviews = window.subviews;
    if ([subviews count] > 1) {
        BOOL alert = [[subviews objectAtIndex:1] isKindOfClass:[UIAlertView class]];
        BOOL action = [[subviews objectAtIndex:1] isKindOfClass:[UIActionSheet class]];

        if (alert || action)
            return YES;
    }
}
return NO;

答案 5 :(得分:1)

-(BOOL)GetKeyWindow {    
        UIViewController *presentedViewController = myAppDelegate.window.rootViewController.presentedViewController;

        if (presentedViewController) {

            if ([presentedViewController isKindOfClass:[UIActivityViewController class]] || [presentedViewController isKindOfClass:[UIAlertController class]]) {        

                return YES;
            }else{
                return NO;
                NSLog(@"not present");
            }   
        }
        else{
            return NO;
        } 
}