对我来说这是一个跟进问题，但实际上是一个新项目。我在查询中分享的一些信息和其他信息我完全无法完成，但我必须谨慎对待其中一些信息。
在这个查询中，我创建了两个临时表，我将引用：
IF OBJECT_ID('tempdb..#SAMHSA_PAT_LIST') IS NOT NULL
DROP TABLE #SAMHSA_PAT_LIST
CREATE TABLE #SAMHSA_PAT_LIST (
MRN VARCHAR(50),
trac_id VARCHAR(50))
INSERT INTO #SAMHSA_PAT_LIST (MRN, trac_id)
VALUES ('XXXXXXXX','001').....
和
INSERT INTO #MentalDX (MHDX)
VALUES ('F03.90'),('F03.91'),('F20.0'),('F20.1').... --hundreds of values
从结构上讲，我接下来会使用以下内容查找特定访问：
IF OBJECT_ID ('tempdb..#grantvisits') IS NOT NULL
DROP TABLE #grantvisits
SELECT
spl.MRN
,spl.trac_id
,pev.CONTACT_DATE AS Visits
INTO
#grantvisits
FROM
#SAMHSA_PAT_LIST spl
INNER JOIN dbo.IDENTITY_ID_VIEW iiv
ON iiv.IDENTITY_ID=spl.MRN
INNER JOIN dbo.PAT_ENC_VIEW pev
ON pev.PAT_ID = iiv.PAT_ID
WHERE
pev.CONTACT_DATE >= @Start_Date
AND pev.CONTACT_DATE < @End_Date
AND iiv.IDENTITY_ID = spl.MRN
AND iiv.IDENTITY_TYPE_ID = XX
AND pev.APPT_STATUS_C IN ( 2 , 6 , 8 , 9 )
然后我查找与第二个临时表中的值匹配的访问：
IF OBJECT_ID ('tempdb..#dxMentalHealth') IS NOT NULL
DROP TABLE #dxMentalHealth
SELECT
gv.MRN
,gv.trac_id
,edg1m.EXTERNAL_ID AS mdx1
,edg2m.EXTERNAL_ID AS mdx2
,edg3m.EXTERNAL_ID AS mdx3
,edg4m.EXTERNAL_ID AS mdx4
,edg5m.EXTERNAL_ID AS mdx5
,edg6m.EXTERNAL_ID AS mdx6
INTO
#dxMentalHealth
FROM
#grantvisits gv
INNER JOIN dbo.IDENTITY_ID_VIEW iiv
ON iiv.IDENTITY_ID=gv.MRN
.....
LEFT JOIN CLARITY_EDG edg1m
ON tdl.DX_ONE_ID = edg1m.DX_ID
AND edg1m.REF_BILL_CODE_SET_C IN ( 1 , 2 , 1001 )-- 1 = ICD9; 2 = ICD10
AND edg1m.REF_BILL_CODE IN ( SELECT md.MHDX FROM #MentalDX md )
....
接下来，我查看这些访问并查找与MentalDX列表特别匹配的dx代码：
IF OBJECT_ID('tempdb..#mdxcounts') IS NOT NULL
DROP TABLE #mdxcounts
SELECT trac_id
,mdx1 AS mdxx
,COUNT(*) AS cnt
INTO #mdxcounts
FROM #dxMentalHealth
WHERE mdx1 IS NOT NULL
GROUP BY
trac_id
,mdx1
UNION
SELECT trac_id
,mdx2
,COUNT(*) AS cnt
FROM #dxMentalHealth
WHERE mdx2 IS NOT NULL
GROUP BY
trac_id
,mdx2
UNION
SELECT trac_id
,mdx3
,COUNT(*) AS cnt
FROM #dxMentalHealth
WHERE mdx3 IS NOT NULL
GROUP BY
trac_id
,mdx3
UNION
SELECT trac_id
,mdx4
,COUNT(*) AS cnt
FROM #dxMentalHealth
WHERE mdx4 IS NOT NULL
GROUP BY
trac_id
,mdx4
UNION
SELECT trac_id
,mdx5
,COUNT(*) AS cnt
FROM #dxMentalHealth
WHERE mdx5 IS NOT NULL
GROUP BY
trac_id
,mdx5
UNION
SELECT trac_id
,mdx6
,COUNT(*) AS cnt
FROM #dxMentalHealth
WHERE mdx6 IS NOT NULL
GROUP BY
trac_id
,mdx6;
接下来我非常感谢@SqlZim让我在这里重新使用his answer for a slightly different problem：
IF OBJECT_ID('tempdb..##mdxpivot') IS NOT NULL
DROP TABLE ##mdxpivot
declare @cols nvarchar(max);
declare @select_cols nvarchar(max);
declare @sql nvarchar(max);
select @cols = stuff((
select distinct
',' + quotename('mdxtemp'
+ right('0' +convert(nvarchar(10),row_number() over (
partition by trac_id
order by cnt
)),2)
)
from #mdxcounts
for xml path (''), type).value('.','nvarchar(max)')
,1,1,'');
select @select_cols = (
select distinct
char(10)+' , ' + quotename('mdxtemp'
+ right('0' +convert(nvarchar(10),row_number() over (
partition by trac_id
order by cnt
)),2)
) +' = isnull('+
quotename('mdxtemp'
+ right('0' +convert(nvarchar(10),row_number() over (
partition by trac_id
order by cnt
)),2)
)+','''')'
from #mdxcounts
for xml path (''), type).value('.','nvarchar(max)')
select @sql = '
select trac_id' + @select_cols + '
into ##mdxpivot
from (
select
trac_id
, mdxx
, rn=''mdxtemp''+right(''0'' +convert(nvarchar(10),row_number() over (
partition by trac_id
order by cnt
)),2)
from #mdxcounts
) as a
pivot (max([mdxx]) for [rn] in (' + @cols + ') ) p'
--select @sql as CodeGenerated
exec sp_executesql @sql
我需要做的是按计数对mdxtemp *列中的值进行排序。作为参考并显示我还没有看到#mdxcounts表中三个trac_id的结果如下：
trac_id mdxx cnt
1 F33.1 504
1 F07.81 378
1 F31.9 189
5 F33.9 1825
5 F50.00 1400
5 F20.9 975
5 F20.3 700
5 F43.10 700
5 F43.10 625
5 F20.3 625
5 F19.10 625
10 F31.9 1547
10 F25.0 169
10 R45.851 91
10 R44.0 91
10 F31.74 39
但##mdxpivot的结果显示如下：
trac_id mdxtemp01 mdxtemp02 mdxtemp03 mdxtemp04 mdxtemp05 mdxtemp06 mdxtemp07 mdxtemp08
001 F31.9 F07.81 F33.1
005 F43.10 F20.3 F19.10 F43.10 F20.3 F20.9 F50.00 F33.9
010 F31.74 R44.0 R45.851 F25.0 F31.9
如何重新排序值？此外，我将不得不在查询中第二次执行此操作，而不是#MentalDX临时表中的所有DX代码。我是否必须用略微不同的名称重做所有声明？