在SQL Server中出现值时将行拆分为列

Question

我有一个包含此值的表：

ITPROD  PROD1   PROD2   Quantity 1  Quantity 2
45842   69640   63908      3               2
70690   91387   90734      1               2

结果表应为：

ITPROD   PROD       Quantity    
45842    69640         3           
45842    63908         2           
70690    91387         1           
70690    90734         2           

Answer 1

select itprod, prof1 as prod, quantity1 as quantity from your_table
union all
select itprod, prof2, quantity2 from your_table

Answer 2

将cross apply()与values()一起使用：

select 
    t.itprod
  , v.Prod
  , v.Quantity
from t
  cross apply (values 
      (Prod1,Quantity1)
    , (Prod2,Quantity2)
    ) v(Prod,Quantity)

rextester演示：http://rextester.com/MFDCA68129

返回：

+--------+-------+----------+
| itprod | Prod  | Quantity |
+--------+-------+----------+
|  45842 | 69640 |        3 |
|  45842 | 63908 |        2 |
|  70690 | 91387 |        1 |
|  70690 | 90734 |        2 |
+--------+-------+----------+

Answer 3

试试这个，

SELECT ITPROD   AS ITPROD,PROD1  AS PROD,Quantity1  AS Quantity1 FROM SampleTable
UNION ALL
SELECT ITPROD   AS ITPROD,PROD2  AS PROD,Quantity2  AS Quantity1 FROM SampleTable